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Svet_ta [14]
3 years ago
7

Which table corresponds to the fiction y=-3x+5

Mathematics
1 answer:
SVETLANKA909090 [29]3 years ago
4 0
Please send another link you only show D
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What conclusions can be drawn about finding the quotient in scientific notation? Check all that apply.
irga5000 [103]

Answer:

B.The exponent of the solution is –12, the difference of the original exponents.

C.The coefficient of the solution must be greater than or equal to one but less than 10.

D.The quotient is 3.0 ×

Step-by-step explanation:

7 0
2 years ago
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Simplify<br><br> x^4 * x <br><br> What would be the simplified answer
kramer

Answer: The simplified answer will be: x^5

Step-by-step explanation:

x4x

=x4*x1

=(x*x*x*x)*(x)

=x*x*x*x*x

=x^5

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2 years ago
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If f(x) = 3x -11 , find -4f (-3)
gladu [14]

Answer:

80

Step-by-step explanation:

-4f(x)=-12x+44

-4f(-3)=36+44=80

6 0
3 years ago
The length is 2 feet longer than the width. The perimeter is 36 feet, what is the length?
SOVA2 [1]

Answer:

The length would be 10ft and the width would be 8ft

Step-by-step explanation:

For the purpose of this, we'll set the width as x. We can then define the length as x + 2 since we know it is 2 ft longer than the width. Now we can use those along with the perimeter formula to solve for the width.

P = 2l + 2w

36 = 2(x + 2) + 2(x)

36 = 2x + 4 + 2x

36 = 4x + 4

32 = 4x

8 = x

Now since we know that the width is 8ft, we can add 2ft to it to get the length, which would be 10ft.

4 0
3 years ago
Q.6. The equation of the ellipse whose centre is at the origin and the x-axis, the major axis, which passes
azamat

<h3>Answer:</h3>

Equation of the ellipse = 3x² + 5y² = 32

<h3>Step-by-step explanation:</h3>

<h2>Given:</h2>

  • The centre of the ellipse is at the origin and the X axis is the major axis

  • It passes through the points (-3, 1) and (2, -2)

<h2>To Find:</h2>

  • The equation of the ellipse

<h2>Solution:</h2>

The equation of an ellipse is given by,

\sf \dfrac{x^2}{a^2} +\dfrac{y^2}{b^2} =1

Given that the ellipse passes through the point (-3, 1)

Hence,

\sf \dfrac{(-3)^2}{a^2} +\dfrac{1^2}{b^2} =1

Cross multiplying we get,

  • 9b² + a² = 1 ²× a²b²
  • a²b² = 9b² + a²

Multiply by 4 on both sides,

  • 4a²b² = 36b² + 4a²------(1)

Also by given the ellipse passes through the point (2, -2)

Substituting this,

\sf \dfrac{2^2}{a^2} +\dfrac{(-2)^2}{b^2} =1

Cross multiply,

  • 4b² + 4a² = 1 × a²b²
  • a²b² = 4b² + 4a²-------(2)

Subtracting equations 2 and 1,

  • 3a²b² = 32b²
  • 3a² = 32
  • a² = 32/3----(3)

Substituting in 2,

  • 32/3 × b² = 4b² + 4 × 32/3
  • 32/3 b² = 4b² + 128/3
  • 32/3 b² = (12b² + 128)/3
  • 32b² = 12b² + 128
  • 20b² = 128
  • b² = 128/20 = 32/5

Substituting the values in the equation for ellipse,

\sf \dfrac{x^2}{32/3} +\dfrac{y^2}{32/5} =1

\sf \dfrac{3x^2}{32} +\dfrac{5y^2}{32} =1

Multiplying whole equation by 32 we get,

3x² + 5y² = 32

<h3>Hence equation of the ellipse is 3x² + 5y² = 32</h3>
8 0
3 years ago
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