All categories

3 years ago

Can someone please help?

Mathematics

2 answers:

Scorpion4ik [409]3 years ago

8 0

It’s the third one. .

mylen [45]3 years ago

7 0

$9 \times \frac{1}{4} = \frac{9}{4}$ ✅

<h3>Step-by-step explanation:</h3>

Option A⤵

$5 \times \frac{1}{2} = \frac{1}{10} \\ ⇢ \frac{5}{2} ≠ \frac{1}{10}$

Option B⤵

$4 \times \frac{1}{3} = \frac{4}{12} \\ ⇢ \frac{4}{3} ≠ \frac{4}{12}$

Option C⤵

$9 \times \frac{1}{4} = \frac{9}{4} \\ ⇢ \frac{9}{4} = \frac{9}{4}$

Option D⤵

$8 \times \frac{1}{ 5} = \frac{9}{5} \\ ⇢ \frac{8}{5} ≠ \frac{9}{5}$

Hence, option C is correct.

$\circ \: \: { \underline{ \boxed{ \sf{ \color{green}{Happy\:learning.}}}}}∘$

You might be interested in

An employee compiled sales data for a company once each month. The scatter plot below shows the sales (in multiples of $1000) fo

Y_Kistochka [10]

The answer is e $940

5 0

3 years ago

Read 2 more answers

...............................help!!!

Ray Of Light [21]

Answer:

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Given: PRST is a square

xxTIMURxx [149]

Answer:

$(1-\sqrt{2})a^2$

Step-by-step explanation:

Consider irght triangle PRS. By the Pythagorean theorem,

$PS^2=PR^2+RS^2\\ \\PS^2=a^2+a^2\\ \\PS^2=2a^2\\ \\PS=\sqrt{2}a$

Thus,

$MS=PS-PM=\sqrt{2}a-a=(\sqrt{2}-1)a$

Consider isosceles triangle MSC. In this triangle

$MS=MC=(\sqrt{2}-1)a.$

The area of this triangle is

$A_{MSC}=\dfrac{1}{2}MS\cdot MC=\dfrac{1}{2}\cdot (\sqrt{2}-1)a\cdot (\sqrt{2}-1)a=\dfrac{(\sqrt{2}-1)^2a^2}{2}=\dfrac{(3-2\sqrt{2})a^2}{2}$

Consider right triangle PTS. The area of this triangle is

$A_{PTS}=\dfrac{1}{2}PT\cdot TS=\dfrac{1}{2}a\cdot a=\dfrac{a^2}{2}$

The area of the quadrilateral PMCT is the difference in area of triangles PTS and MSC:

$A_{PMCT}=\dfrac{(3-2\sqrt{2})a^2}{2}-\dfrac{a^2}{2}=\dfrac{(2-2\sqrt{2})a^2}{2}=(1-\sqrt{2})a^2$

5 0

3 years ago

Suppose there is a 13.9 % probability that a randomly selected person aged 40 years or older is a jogger. In addition, there is

Blababa [14]

Answer:

There is a 2.17% probability that a randomly selected person aged 40 years or older is male and jogs.

It would be unusual to randomly select a person aged 40 years or older who is male and jogs.

Step-by-step explanation:

We have these following probabilities.

A 13.9% probability that a randomly selected person aged 40 years or older is a jogger, so $P(A) = 0.13$ .

In addition, there is a 15.6% probability that a randomly selected person aged 40 years or older is male comma given that he or she jogs. I am going to say that P(B) is the probability that is a male. $P(B/A)$ is the probability that the person is a male, given that he/she jogs. So $P(B/A) = 0.156$

The Bayes theorem states that:

$P(B/A) = \frac{P(A \cap B)}{P(A)}$

In which $P(A \cap B)$ is the probability that the person does both thigs, so, in this problem, the probability that a randomly selected person aged 40 years or older is male and jogs.

$P(A \cap B) = P(A).P(B/A) = 0.156*0.139 = 0.217$

There is a 2.17% probability that a randomly selected person aged 40 years or older is male and jogs.

A probability is unusual when it is smaller than 5%.

So it would be unusual to randomly select a person aged 40 years or older who is male and jogs.

4 0

3 years ago

If 2x squared + 8y = 121. 5, what is x

mezya [45]

X=30.4-2y
(step by step) :

5 0

3 years ago