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kotegsom [21]
3 years ago
6

$7.50 admission; 20% off 5.75% tax

Mathematics
1 answer:
yuradex [85]3 years ago
8 0

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Let U = {1, 2, 3, 4, 5, 6, 7}, A= {1, 3, 4, 6}, and B= {3, 5, 6}. Find the set A’ U B’
Art [367]

Answer:

Step-by-step explanation:

A'={2,5,7}

B'={1,2,4,7}

A'UB'={1,2,4,5,7}

8 0
3 years ago
Least to greatest 1/2, 2/5, 6/10
Elza [17]
Answer : 2/5, 1/2, 6/10
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Read 2 more answers
Please answer the question from the attachment.
Mars2501 [29]
We have to calculate the pizza´s area.
r=radius
Area (circle)=π*r²
diameter=30 cm
radius=diameter/2=30 cm/2=15 cm

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solution: 706.86 cm²
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3 years ago
17.The diameter of a circle has endpoints P(–7, –10) and Q(3, 2).
ser-zykov [4K]
A.) (-2,-4)
(7+3)/2=5, (10+2)/2=6
(-7+5,-10+6)
(-2,-4)
b.)r^2=244
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7 0
3 years ago
A trucking firm has a large inventory of spare parts that have been in storage for a long time. It knowsthat some proportion of
Debora [2.8K]

Answer:

0.1546\leq \widehat{p}\leq 0.3513

Step-by-step explanation:

The firm tests 75 parts, and finds that 0.25 of them are notusable

n = 75

x = 0.25 \times 75 = 18.75≈19

\widehat{p}=\frac{x}{n}

\widehat{p}=\frac{19}{75}

\widehat{p}=0.253

Confidence level = 95%

So, Z_\alpha at 95% = 1.96

Formula of confidence interval of one sample proportion:

=\widehat{p}-Z_\alpha \sqrt{\frac{\widehat{p}(1-\widehat{p}}{n}}\leq \widehat{p}\leq \widehat{p}+Z_\alpha \sqrt{\frac{\widehat{p}(1-\widehat{p}}{n}}

=0.253-(1.96)\sqrt{\frac{0.253(1-0.253)}{75}}\leq \widehat{p}\leq0.253+(1.96)\sqrt{\frac{0.253(1-0.253}{75}}

Confidence interval =0.1546\leq \widehat{p}\leq 0.3513

7 0
3 years ago
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