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emmasim [6.3K]
3 years ago
14

Round to 3 SF 0.0692494

Mathematics
2 answers:
cupoosta [38]3 years ago
6 0

rounding 0.0692494 to 3SF is 0.069

telo118 [61]3 years ago
5 0
The first three significant digits are 692
Rounding 0.0692494 = 0.0692 (3 sf)
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Q # 19 The data below shows the. number of hours a week on average group of students spend volunteering for community service pr
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If those two are your only choices then the answer is none of the above. 

<em>Attached is a cumulative frequency table for your data.</em>

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7 0
3 years ago
Evaluate lim x→∞ (3x+1)^(4/x), using l'hospital's rule as needed. show all work using proper notation. as you show your work, if
Alborosie
\displaystyle\lim_{x\to\inty}(3x+1)^{4/x}=\lim_{x\to\infty}e^{\ln(3x+1)^{4/x}}=e^{\lim\limits_{x\to\infty}\ln(3x+1)^{4/x}}

\displaystyle\lim_{x\to\infty}\ln(3x+1)^{4/x}=\lim_{x\to\infty}\frac{4\ln(3x+1)}x\stackrel{\mathrm{LHR}}=\lim_{x\to\infty}\frac{4\frac3{3x+1}}1=\lim_{x\to\infty}\frac{12}{3x+1}=0

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4 0
3 years ago
Solve the equation. 9 - 19= 18 9​=
marishachu [46]

Answer:

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2 years ago
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Uhh, answer choices?

In any case, since \triangle KJL is inscribed in a semicircle, it is a right triangle (due to the inscribed angle theorem). Thus, by the Pythagorean theorem, KL=\sqrt{6^2+11^2}=\sqrt{157}. Now, the circumradius of a right triangle (the radius of the circle passing through all three of its vertices) is simply half its hypotenuse, so OJ=OK=OL=\frac{\sqrt{157}}{2}\approx \boxed{6.265}.

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<span>x^2+y^2=49
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