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DiKsa [7]
3 years ago
5

Thank you all for the help! What is standard form for 2 times 2 times 2

Mathematics
2 answers:
eduard3 years ago
7 0

Answer:

your not welcome

Step-by-step explanation:

Svetach [21]3 years ago
3 0

2 to the power of 3.

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PLZ HELP! Use technology or a z-score table to answer the question.
Rashid [163]

Answer:

the answer would be A, or 5.3%

Step-by-step explanation:

you start by finding the z-score of 200, so 200-144.05 = 55.95/34.52 = 1.62 (rounded to the nearest ) Then you use a z-score table to find the probability that a customer will spend less than 200 dollars and subtract the decimal probability from one. then you convert the decimal probability to a percent and get 5.3%.

7 0
3 years ago
HELP PLEASE!!! I need help with 94 if you could show the steps that would be very helpful!
aksik [14]
A combination is an unordered arrangement of r distinct objects in a set of n objects. To find the number of permutations, we use the following equation:

n!/((n-r)!r!)

In this case, there could be 0, 1, 2, 3, 4, or all 5 cards discarded. There is only one possible combination each for 0 or 5 cards being discarded (either none of them or all of them). We will be the above equation to find the number of combination s for 1, 2, 3, and 4 discarded cards.

5!/((5-1)!1!) = 5!/(4!*1!) = (5*4*3*2*1)/(4*3*2*1*1) = 5

5!/((5-2)!2!) = 5!/(3!2!) = (5*4*3*2*1)/(3*2*1*2*1) = 10

5!/((5-3)!3!) = 5!/(2!3!) = (5*4*3*2*1)/(2*1*3*2*1) = 10

5!/((5-4)!4!) = 5!/(1!4!) = (5*4*3*2*1)/(1*4*3*2*1) = 5

Notice that discarding 1 or discarding 4 have the same number of combinations, as do discarding 2 or 3. This is being they are inverses of each other. That is, if we discard 2 cards there will be 3 left, or if we discard 3 there will be 2 left.

Now we add together the combinations

1 + 5 + 10 + 10 + 5 + 1 = 32 choices combinations to discard.

The answer is 32.

-------------------------------

Note: There is also an equation for permutations which is:

n!/(n-r)!

Notice it is very similar to combinations. The only difference is that a permutation is an ORDERED arrangement while a combination is UNORDERED.

We used combinations rather than permutations because the order of the cards does not matter in this case. For example, we could discard the ace of spades followed by the jack of diamonds, or we could discard the jack or diamonds followed by the ace of spades. These two instances are the same combination of cards but a different permutation. We do not care about the order.

I hope this helps! If you have any questions, let me know :)








7 0
3 years ago
Dylan has 128 prices of candy from Halloween . he eats half of his candy each week.
Scilla [17]

Answer:

55.5 left over.

Step-by-step explanation:

128/2 = 64

half each week so;

1 whole = two weeks

8 weeks = 8

+ 1 = 8 1/2

so, 64/8.5

is going to be 55.5 left.

5 0
3 years ago
Give two examples of line segments that will make a triangle ?
77julia77 [94]

Answer:

If the length of any one side is greater than the sum of the length of the other two, the line segments cannot be used to create a triangle. It is possible to create a triangle using 3 line segments if the sum of the lengths of any two line segments is greater than the length of the third.

7 0
3 years ago
Which graph shows the solution set for |x - 3| < 4?
ikadub [295]

Answer:

see below

Step-by-step explanation:

|x - 3| < 4

To remove the absolute values, we need to make two inequalities, one positive and one negative

x-3 < 4     and     x-3 > -4

Add 3 to each side

x-3+3<4+3     and  x-3+3 > -4+3

x<7        and        x >-1

-1 <x <7

4 0
3 years ago
Read 2 more answers
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