All categories

2 years ago

Just look at the pictures I really need help

Mathematics

1 answer:

Aleksandr [31]2 years ago

8 0

Answer:

Step-by-step explanation:

It can be shown that all four sides of this figure have the same length. This, in turn, is the definition of a rhombus.

You might be interested in

Which two FRACTIONS below have a DIFFERENCE of 27/40?

Xelga [282]

I think the answer is 2 3/5 and 11/5

4 0

2 years ago

Read 2 more answers

PLEASE HELP making brainliest if correct

zloy xaker [14]

Yes they are congruent because both of them are equilateral triangles

8 0

2 years ago

Alvin is 15 younger than elga the sum of their age is 27 what is elga age

zloy xaker [14]

Answer:

27 years old

Step-by-step explanation:

Let Alvin's age be x and Elga's age is y:

y - x = 15

x + y = 27

2y = 42 (use elimination method)

y = 21

x = 6 (plug it back into either equation)

Therefore Alvin is 6 and Elga is 27

7 0

2 years ago

Read 2 more answers

Put the differential equation 9ty+ety′=yt2+81 into the form y′+p(t)y=g(t) and find p(t) and g(t). p(t)= help (formulas) g(t)= he

alexgriva [62]

Answer:

$p(t) = \frac{9t^{3} + 729t - 1}{e^{t}(t^{2} + 81) }$

g(t) = 0

And

The differential equation $9ty + e^{t}y' = \frac{y}{t^{2} + 81 }$ is linear and homogeneous

Step-by-step explanation:

Given that,

The differential equation is -

$9ty + e^{t}y' = \frac{y}{t^{2} + 81 }$

$e^{t}y' + (9t - \frac{1}{t^{2} + 81 } )y = 0\\e^{t}y' + (\frac{9t(t^{2} + 81 ) - 1}{t^{2} + 81 } )y = 0\\e^{t}y' + (\frac{9t^{3} + 729t - 1}{t^{2} + 81 } )y = 0\\y' + [\frac{9t^{3} + 729t - 1}{e^{t}(t^{2} + 81) } ]y = 0$

By comparing with y′+p(t)y=g(t), we get

$p(t) = \frac{9t^{3} + 729t - 1}{e^{t}(t^{2} + 81) }$

g(t) = 0

And

The differential equation $9ty + e^{t}y' = \frac{y}{t^{2} + 81 }$ is linear and homogeneous.

6 0

2 years ago

The area of trapezium is 1586cm² and the distance between sides is 26cm.If one of the parallel sides is 84cm,find the other

irinina [24]

Check the picture below.

we know the area is 1586, so

$\stackrel{\textit{area of a trapezoid}}{A=\cfrac{h(a+b)}{2}}\implies 1586=\cfrac{26(84+b)}{2}\implies 1586=13(84+b) \\\\\\ \cfrac{1586}{13}=84+b\implies 122=84+b\implies 38=b$

3 0

2 years ago