<h2>Area = 80 ft²</h2><h2>------------------------------</h2>
<u>Step-by-step explanation:</u>
diagonal 1 (d1) = 5 + 5
= 10 ft
diagonal 2 (d2) = 8 + 8
= 16 ft
area of rhombus = 1/2 × d1 × d2
= 1/2 × 10 × 16
= 80 ft²
<h2>--------------------------------</h2><h2>Follow me</h2>
Answer:
Step-by-step explanation:
<u>The Number Line</u>
Let's call
Both numbers are given as mixed fractions. Let's convert them to improper fractions:
The decimal values are A = -9/2=-4.5, B=13/4 = 3.25
Now represent the points in the number line. See the image below
Finally, calculate their sum:
x = 56°
Solution:
Part A:
Given data:
2x and 68° are adjacent angles in a straight line and their measures have sum of 180°.
Part B:
<em>Sum of the adjacent angles in the straight line is 180°.</em>
2x + 68° = 180°
Subtract 68° from 180°, we get
⇒ 2x = 112°
Divide by 2 on both sides, we get
⇒ x = 56°
The value of x is 56°.
Part C:
By part A and part B,
2x° + 68° = 2(56°) + 68°
= 112° + 68°
= 180°
2x° + 68° = 180°
Hence proved.
The question states the the graph is non-vertical. This mean the graph is either rise of falling. This also means that the value of function is not same at more than one value of x.
Another hint the question gives us is that the graph is a straight line. So this means we have a straight line rising or falling with some angle or a slope. This signifies a linear function.
It would have been a non-function if the line was a vertical one.
It would have been a non-linear function if the line was not straight.
The graph of exponential function is not straight.
Hence the answer to this question is Linear Function
Answer:
Therefore the height of the water in the pool changes at the rate of 
feet per minute.
Step-by-step explanation:
Given that the shape of swimming pool is right circular cylinder.
The rate of water pouring in the pool = 3 cubic feet per minute.
It means the rate of change of volume is 3 cubic feet per minute.
cubic feet per minute.
When the volume of the swimming pool changed it means the height of the water level of the pool change and the radius of the swimming pool remains constant.
Let the height of the pool be h.
The volume of the pool is = 
cubic feet
cubic feet
Therefore,
v
Differentiating with respect to t
Putting
The change of height of the pool does not depend on the depth of the pool.
Therefore the rate of change of height of the water in the pool is feet per minute.
