An absolute value of any number cannot result in a negative number.
There are no possible points where |x| can equal -5.
Given:
3kg book
speed of falling of 4.0 m/s
acceleration due to gravity -9.8 m/s²
Vf² = Vi² + 2 * a * d
Vf = final velocity ; Vi = initial velocity ; a = acceleration ; d = distance
0² = (4 m/s)² + 2(-9.8m/s²) * d
0 = 16 m²/s² -19.6 m/s² * d
-16 m²/s² = -19.6 m/s² * d
-16 m²/s² / -19.6 m/s² = d
0.82 m = distance
The 3 kg book fell from the a shelf at the height of 0.82 meters.
Answer:
i doing this it is one
Step-by-step explanation:
The line is solid so we have either ≤ or ≥
find the equation of the line
ok, a y intercept if -1
sllope=rise/run=3/1=3
y=mx+b
m=slope
b=y intercept
y=3x-1 is the equaton
now find if it's y≥3x-1 or y≤3x-1
test a point
we see (0,0) Is not in in it
test it in y≥3x-1
0≥3(0)-1
0≥-1
false,
so this is the equation because (0,0) is not a valid solution for this equation
answer is y≥3x-1
