All categories

3 years ago

what is the equation of the line in point slope form that goes through (-2,-1) and is perpendicular to y=5x+3?

1 answer:

8 0

Point slope form is $y-y1=m(x-x1)$

Since we have to write the equation of a perpendicular line we will have to use the slope that is opposite and reciprocal.

$y - (-1) = - \frac{1}{5} (x - (-2))$
$y + 1 = - \frac{1}{5} (x + 2)$

Hope this helps :)

You might be interested in

Which equation could be used to solve the following problem?

-BARSIC- [3]

115 +10p =305

Step-by-step explanation:

given,

let p day it takes

So,115+10p =305

4 0

2 years ago

Put them in order from least to greatest:<br> 9.5 9.66 9.662 9.551 9 9.59 9.626

Fiesta28 [93]

Answer:

9, 9.5,9.551,9.59,9.626,9.66,9.662

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Can someone help me with this problem

Alex_Xolod [135]

Answer:

Step-by-step explanation:

The formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

A(-3, 0) , B(3, 2)

$AB=\sqrt{(3-(-3))^2+(2-0)^2}=\sqrt{6^2+2^2}=\sqrt{36+4}=\sqrt{40}=\sqrt{4\cdot10}=\sqrt4\cdot\sqrt{10}=2\sqrt{10}$

A(-3, 0), D(-2, -3)

$AD=\sqrt{(-2-(-3))^2+(-3-0)^2}=\sqrt{1^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}$

AB = CD and AD = BC

The area of a rectangle:

$A=(AB)(AD)$

Substitute:

$A=(2\sqrt{10})(\sqrt{10})=(2)(10)=20$

The perimeter of a rectangle:

$P=2(AB+AD)$

Substitute:

$P=2(2\sqrt{10}+\sqrt{10})=2(3\sqrt{10})=6\sqrt{10}$

4 0

3 years ago

The world population in 2000 was approximately 6.08 billion. The annual rate of increase

Anestetic [448]

Answer:

Step-by-step explanation:

8 0

3 years ago

Plz help 7th grade math

AysviL [449]

Divide 9 from 5 and you should get the range

6 0

3 years ago