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2 years ago

Suppose that 2 ≤ f '(x) ≤ 4 for all values of x. What are the minimum and maximum possible values of

Mathematics

1 answer:

Vesna [10]2 years ago

5 0

Answer:

Step-by-step explanation:

By the Mean Value Theorem, there is at least one number, c, in the interval (1,6) such that

f'(c) = [f(6) - f(1)]/ (6 - 1)

So, f(6) - f(1) = 5f'(c).

Since 2 ≤ f'(c) ≤ 4, 10 ≤ 5f'(c) ≤ 20

So, f(6) - f(1) is between 10 and 20.

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You roll a number cube find the probability. P(3 or 4)

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Say the cube has sides numbered 1-6 that means there are 6 possible outcomes. 3 and 4 are only two possible outcomes so the probability of that is 2:6. Simply 1:3 or 33%

3 0

3 years ago

Read 2 more answers

1. __% of 4 is 7 <br><br> 2.__% of 75 is 25

jekas [21]

Answer:

1. 57.142857142857%

2. 33.33

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3 years ago

Use the numbers 8, 6, and 2 and one operation to write and expression that includes an exponent and has a value of 8. Use each n

Vesnalui [34]

Answer:

$6+2^{1}=8 \Rightarrow 6+2=8 \Rightarrow 8=8$

Step-by-step explanation:

1) One solution is to write, as our exponent:

$2^{1}=2$

2) Because this is special case of the Exponents Law, valid for every base ≠ 0.

$a^{1}=a$

3) Hence, including an exponent the numbers 6, 2 whose value is eight.

$6+2^{1}=8 \Rightarrow 6+2=8 \Rightarrow 8=8$

Therefore our expression is true

4 0

3 years ago

Read 2 more answers

How would u solve this??

Norma-Jean [14]

Answer:

n=1, m=3, and p=-4

Step-by-step explanation:

Take the fourth root of both sides

so x^n*y^m*z^p=x*y^3*z^-4;

notice z has a negative exponent because it was in the denominator

therefore, n=1, m=3, and p=-4

4 0

3 years ago

Work out (5x10³) x (9x10)

nasty-shy [4]

Answer:

4.5 × 10^5 or 450000 :)))))

6 0

3 years ago