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Liula [17]
2 years ago
6

Suppose that 2 ≤ f '(x) ≤ 4 for all values of x. What are the minimum and maximum possible values of

Mathematics
1 answer:
Vesna [10]2 years ago
5 0

Answer:

Step-by-step explanation:

By the Mean Value Theorem, there is at least one number, c, in the interval (1,6) such that

f'(c) = [f(6) - f(1)]/ (6 - 1)

So, f(6) - f(1) = 5f'(c).

Since 2 ≤ f'(c) ≤ 4, 10 ≤ 5f'(c) ≤ 20

So, f(6) - f(1) is between 10 and 20.  

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15 - (4m - 5) + 32

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=- 4m + 52

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3 years ago
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3

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3 years ago
Two teachers purchase supplies for their classrooms.
inna [77]

Answer:

Cost of One Journal =  $3.99

Cost of One pen =  $0.59

Step-by-step explanation:

Let

Cost of One Journal = x

Cost of One pen = y

We can make equation from given statements.

Mr. Bowden purchases 18 journals and 40 pencils for $95.42.

18x+40y=95.42

Ms. Jacinto purchases 11 journals and 16 pencils for $53.33.

11x+16y=53.33

Now solving these equations to find the value of x

18x+40y=95.42--eq(1)\\11x+16y=53.33--eq(2)

Multiply eq(1) with 2 and eq(2) with 5

36x+80y=190.84\\55x+80y=266.65\\-\:\:\:\:-\:\:\:\;\:\:\:\:\:\:\:-\\---------\\-19x=-75.81\\x=\frac{-75.81}{-19}\\x=3.99\\

We get the value of x is: x=3.99

Now, putting value of x in equation 1 to find value of y.

18x+40y=95.42\\18(3.99)+40y=95.42\\71.82+40y=95.42\\40y=95.42-71.82\\40y=23.6\\y=\frac{23.6}{40}\\y= 0.59

So, we get the value of y: y = 0.59

Now, finding the costs:

Cost of One Journal = x = $3.99

Cost of One pen = y = $0.59

7 0
3 years ago
Compare Decima<br> 2.48 [. ] 2.53<br><br> I need help finishing if this is a &lt;,&gt; or =
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Answer: <

Step-by-step explanation:

2.48 < 2.53

7 0
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