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Liula [17]
2 years ago
6

Suppose that 2 ≤ f '(x) ≤ 4 for all values of x. What are the minimum and maximum possible values of

Mathematics
1 answer:
Vesna [10]2 years ago
5 0

Answer:

Step-by-step explanation:

By the Mean Value Theorem, there is at least one number, c, in the interval (1,6) such that

f'(c) = [f(6) - f(1)]/ (6 - 1)

So, f(6) - f(1) = 5f'(c).

Since 2 ≤ f'(c) ≤ 4, 10 ≤ 5f'(c) ≤ 20

So, f(6) - f(1) is between 10 and 20.  

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3 years ago
What is the length of BC​
elena55 [62]

Answer:

BC = 2

Step-by-step explanation:

We first need to use triangle BAD to find BD,

BD is the hypotenuse, so use pythagorean theorem...

      (√23)² + (√13)² = (BD)²

            23 + 13 = (BD)²

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                  6 = BD

Now BD is the hypotenuse of triangle BCD, so use pythagorean theorem agian to find BC

     (4√2)² + (BC)² = 6²

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3 0
3 years ago
Which function is negative for the interval (–1, 1]?
Taya2010 [7]
I think it’s the second one
7 0
3 years ago
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How do I find the answer for this equation 20x+15y= 330, when x+y =18
Maru [420]
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6 0
3 years ago
Help with this please, picture above ^
Irina18 [472]

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8 0
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