Answer:
Step-by-step explanation:
Given points moves b/w 0.1 of 0.3 marks Hence amplitude is 0.2
Also , frequency (w) = 100 rad/s.
Natural frequency (wn) = √K/m
K = 20 N/mm x 1000mm/1m = 20000N/M
W = 1000mm/1m = 20,000N/M
FormulaX = FolK/1 - (w/wn)²
0.2 = b/20000/1 - (100/50)²
Given forcing frequency was doubled, W1 = 2 x 100=200rad/s
X1 =b/20,000/1 - (200/20)²
0.2/11 = 1 - (200/50)²/1 - (100/50)² = 0.2/11 = -15^5– 3
X1 = 0.04
9514 1404 393
Answer:
(8.49; 225°)
Step-by-step explanation:
The angle is a 3rd-quadrant angle. The reference angle will be ...
arctan(-6/-6) = 45°
In the 3rd quadrant, the angle is 45° +180° = 225°.
The magnitude of the vector to the point is its distance from the origin:
√((-6)² +(-6)²) = √(6²·2) = 6√2 ≈ 8.4859 ≈ 8.49
The polar coordinates can be written as (8.49; 225°).
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<em>Additional comment</em>
My preferred form for the polar coordinates is 8.49∠225°. Most authors use some sort of notation with parentheses. If parentheses are used, I prefer a semicolon between the coordinate values so they don't get confused with an (x, y) ordered pair that uses a comma. You need to use the coordinate format that is consistent with your curriculum materials.
The segment connecting a point on the preimage is equal to the segment connecting the point with its corresponding point on the image. Hence the relationship between the line of reflection is B. perpendicular bisector. It is not necessarily perpendicular as there are axis of symmetry that are not linear or 180 degrees
12 1/3 x 4.5 = 55 1/2 feet
-200 + 55 1/2 = -144 1/2
the diver is at -144 1/2 feet