We are given with two functions: f(x) = x + 8 and g(x) = x2 - 6x - 7. In this problem, the value of f(g(2)) is asked. We first substitute g(x) to f(x) resulting to f(x2 - 6x - 7) = x2 - 6x - 7 + 8 = x2 - 6x + 1. If x is equal to 2, then <span>f(g(2)) = 2^</span>2 - 6*2 + 1 equal to -7.
Do you mean
![3 \sqrt[3]{125}](https://tex.z-dn.net/?f=3%20%5Csqrt%5B3%5D%7B125%7D%20)
or
![\sqrt[3]{125}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B125%7D%20)
remember that
![\sqrt[n]{x^m}=x^\frac{m}{n}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%5Em%7D%3Dx%5E%5Cfrac%7Bm%7D%7Bn%7D)
resolve the
![\sqrt[3]{125}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B125%7D)
part first
![\sqrt[3]{125}=](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B125%7D%3D)
![\sqrt[3]{5^3}=](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B5%5E3%7D%3D)



so
![3 \sqrt[3]{125}=3*5=15](https://tex.z-dn.net/?f=3%20%5Csqrt%5B3%5D%7B125%7D%3D3%2A5%3D15%20)
or
![\sqrt[3]{125} =5](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B125%7D%20%3D5)
not sure which one you mean
Answer:
B) -1-6 x +15 = x - 15 +15
Step-by-step explanation:
<u>Explanation</u>:-
Given equation is –1 – 6 x = x – 15
<em>By addition property of equality </em>
<em> ⇒ - 1 - 6 x + 15 = x - 15 +15</em>
⇒ - 6 x + 14 = x
subtracting 'x' on both sides ,we get
⇒ - 6 x -x +14 =0
⇒ - 7 x +14 =0
⇒ -7 x = - 14
Dividing '-7' on both sides , we get
x = 2
<em>The solution of given equation is x = 2</em>
Answer:
x=−12
Step-by-step explanation:
Let's solve your equation step-by-step.
5x+6=2(2x−3)
Step 1: Simplify both sides of the equation.
5x+6=2(2x−3)
5x+6=(2)(2x)+(2)(−3)(Distribute)
5x+6=4x+−6
5x+6=4x−6
Step 2: Subtract 4x from both sides.
5x+6−4x=4x−6−4x
x+6=−6
Step 3: Subtract 6 from both sides.
x+6−6=−6−6