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TEA [102]
3 years ago
6

In 2013 the most expensive cocktail (made with 1858 ‘Cuvee Leonie’ cognac) was sold in Australia for $12,000. What would have be

en the equivalent price just one year later, in 2014?
Mathematics
1 answer:
Mkey [24]3 years ago
8 0

Answer:

$14,000

Step-by-step explanation:

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Which number is 2,678 less than 10,000
lesantik [10]
Less than means to subtract so 2678 less than 10000 will be
=10000-2678
=7322
3 0
3 years ago
Read 2 more answers
The circumference of a circle is 12 inches. What is the radius
IceJOKER [234]
Greetings!

"<span>The circumference of a circle is 12 inches. What is the radius?"...

We can use the formula to find the circumference of circle to solve this:
</span>2 \pi r
<span>
Input the information we know:
</span>2 \pi r=12
<span>
Solve for r, using the properties of equality:

Simplify.
</span>6.28r=12
<span>Divide both sides by 6.28
</span>(6.28r)/6.28=(12)/6.28<span>
Simplify.
</span>r=1.91

The radius is 1.91cm long.

Hope this helps.
-Benjamin
7 0
3 years ago
Help anyone can help me do this question 3,I will mark brainlest.​
malfutka [58]

Answer:

see explanation

Step-by-step explanation:

Calculate the slopes between pairs of the 3 points using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (- 9, 3) and (x₂, y₂ ) = (- 3, 9)

m = \frac{9-3}{-3-(-9)} = \frac{6}{-3+9} = \frac{6}{6} = 1

Repeat with (x₁, y₁ ) = (5, 1) and (x₂, y₂ ) = (- 3, 9)

m = \frac{9-1}{-3-5} = \frac{8}{-8} = - 1

If lines are perpendicular then the product of their slopes = - 1 , then

1 × - 1 = -1

Thus there is a right angle between the 2 lines

Then triangle is right- angled

8 0
3 years ago
What is the radius of a cylinder with 490picm^3 of volume and 10 cm of height
Sholpan [36]
V = pi*r^2*h
V = 490
h = 10
490 = pi*r^2*10
r = 3.95
7 0
3 years ago
Ursula and yi share a submarine sandwich Ursula eats 2/8 of the sandwich yi eats 3/8 of the sandwich how many of the sandwich do
Alex Ar [27]

Answer:

Step-by-step explanation:

the 2 friend eat 5/8

3 0
2 years ago
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