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Romashka-Z-Leto [24]
3 years ago
9

4. A statistician working for the National Basketball Association supplies the television announcers with interesting statistics

. At a certain point in the season, he discovered that in 375 games, 300 were won by the team that was winning the game at the end of the third quarter. The margin of error in a 90% confidence interval estimate of the true proportion of games won by the team leading at the end of the third quarter with the plus-4 adjustment applied is (Show work): (5)
Mathematics
1 answer:
Sonbull [250]3 years ago
7 0

Answer: 0.038

Step-by-step explanation:

Given: Total games : n= 375

Number of games won by  the team that was winning the game at the end of the third quarter. = 300

The proportion (p) of the team that was winning the game at the end of the third quarter: p=\dfrac{300}{375}=0.8

Critical z-value for 90% confidence: z* = 1.645

Margin of error =z^*\sqrt{\dfrac{(1-p)p}{n}}

The margin of error in a 90% confidence interval estimate of p =1.645\sqrt{\dfrac{0.2\times0.8}{300}}\\= 1.645\times\sqrt{0.00053333}\\\\=1.645\times0.0231\\\\=0.0379995\approx$$0.038

Hence, the required margin of error = 0.038

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3 + 5x = 20 + 7x

First subtract 20 to both sides

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Next subtract 5x to both sides (we are trying to get x all in one side)

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Divide 2 to isolate the x

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nasty-shy [4]

Triangle

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Area = 1/2*15 * 9 = 1/2 * 135 = 67.5

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If 75 percent of the employees of a certain company take a winter vacation, 40 percent take a winter and a summer vacation, and
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Answer:

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The graph of the line y = 6x+4 is attached below.

Step-by-step explanation:

The slope-intercept form of the line equation

y = mx+b

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The y-intercept can be determined by setting x = 0 and determining the corresponding value of y.

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Thus, the equation of the line with slope 6 and containing the point (0, 4) will be:

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The graph of the line y = 6x+4 is attached below.

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