1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
shepuryov [24]
3 years ago
13

Find the midpoint of the segment with the given endpoints. (-7.-10) and (-2,2)

Mathematics
2 answers:
boyakko [2]3 years ago
5 0

Answer:

(-9/2,-4)

Step-by-step explanation:

I hope this helps.

worty [1.4K]3 years ago
3 0
(-4.5,-4) is the midpoint
You might be interested in
!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Bingel [31]

Answer:

:;;;,,,

Step-by-step explanation:

^^^^^^^^^!!~~~

5 0
2 years ago
Read 2 more answers
Evaluate the given expression if a​ = 2 and ​b​ = -4 <br> a2-b3
IceJOKER [234]

Answer:

31

Step-by-step explanation:

{a}^{2}  -  {b}^{3}  \\  \\  =  {(2)}^{2}  -  {( - 3)}^{3}  \\  \\  = 4 - ( - 27) \\  \\  = 4 + 27 \\  \\  = 31

5 0
3 years ago
When possible, the best way to esatblish that an observed association is the result of a cuase and effect relation is by means o
vovangra [49]

Answer:

The answer is a well designed experiment.

Step-by-step explanation:

When possible, the best way to establish that an observed association is the result of a cause and effect relation is by means of - well designed experiment.

Cause and effect relation is a relation between events, where one is the result, due to the occurrence of others. A well designed experiment takes place when we consider the cause and effect of events.

4 0
3 years ago
How can the scaling of a line graph be used to mislead a reader?
Anna [14]
Misleading may be present even t<span>hough all graphs may share the same data, and even the </span>slope<span> of the </span><span>data is the same. If the way the data is plotted is not correct, it can change the visual appearance of the angle made by the line on the graph. This is so because each plot has different scales on its vertical axis. As the scales are not correctly shown then there is where the misleading appears.</span>
5 0
3 years ago
Solve the following differential equation using using characteristic equation using Laplace Transform i. ii y" +y sin 2t, y(0) 2
kifflom [539]

Answer:

The solution of the differential equation is y(t)= - \frac{1}{3} Sin(2t)+2 Cos(t)+\frac{5}{3} Sin(t)

Step-by-step explanation:

The differential equation is given by: y" + y = Sin(2t)

<u>i) Using characteristic equation:</u>

The characteristic equation method assumes that y(t)=e^{rt}, where "r" is a constant.

We find the solution of the homogeneus differential equation:

y" + y = 0

y'=re^{rt}

y"=r^{2}e^{rt}

r^{2}e^{rt}+e^{rt}=0

(r^{2}+1)e^{rt}=0

As e^{rt} could never be zero, the term (r²+1) must be zero:

(r²+1)=0

r=±i

The solution of the homogeneus differential equation is:

y(t)_{h}=c_{1}e^{it}+c_{2}e^{-it}

Using Euler's formula:

y(t)_{h}=c_{1}[Sin(t)+iCos(t)]+c_{2}[Sin(t)-iCos(t)]

y(t)_{h}=(c_{1}+c_{2})Sin(t)+(c_{1}-c_{2})iCos(t)

y(t)_{h}=C_{1}Sin(t)+C_{2}Cos(t)

The particular solution of the differential equation is given by:

y(t)_{p}=ASin(2t)+BCos(2t)

y'(t)_{p}=2ACos(2t)-2BSin(2t)

y''(t)_{p}=-4ASin(2t)-4BCos(2t)

So we use these derivatives in the differential equation:

-4ASin(2t)-4BCos(2t)+ASin(2t)+BCos(2t)=Sin(2t)

-3ASin(2t)-3BCos(2t)=Sin(2t)

As there is not a term for Cos(2t), B is equal to 0.

So the value A=-1/3

The solution is the sum of the particular function and the homogeneous function:

y(t)= - \frac{1}{3} Sin(2t) + C_{1} Sin(t) + C_{2} Cos(t)

Using the initial conditions we can check that C1=5/3 and C2=2

<u>ii) Using Laplace Transform:</u>

To solve the differential equation we use the Laplace transformation in both members:

ℒ[y" + y]=ℒ[Sin(2t)]

ℒ[y"]+ℒ[y]=ℒ[Sin(2t)]  

By using the Table of Laplace Transform we get:

ℒ[y"]=s²·ℒ[y]-s·y(0)-y'(0)=s²·Y(s) -2s-1

ℒ[y]=Y(s)

ℒ[Sin(2t)]=\frac{2}{(s^{2}+4)}

We replace the previous data in the equation:

s²·Y(s) -2s-1+Y(s) =\frac{2}{(s^{2}+4)}

(s²+1)·Y(s)-2s-1=\frac{2}{(s^{2}+4)}

(s²+1)·Y(s)=\frac{2}{(s^{2}+4)}+2s+1=\frac{2+2s(s^{2}+4)+s^{2}+4}{(s^{2}+4)}

Y(s)=\frac{2+2s(s^{2}+4)+s^{2}+4}{(s^{2}+4)(s^{2}+1)}

Y(s)=\frac{2s^{3}+s^{2}+8s+6}{(s^{2}+4)(s^{2}+1)}

Using partial franction method:

\frac{2s^{3}+s^{2}+8s+6}{(s^{2}+4)(s^{2}+1)}=\frac{As+B}{s^{2}+4} +\frac{Cs+D}{s^{2}+1}

2s^{3}+s^{2}+8s+6=(As+B)(s²+1)+(Cs+D)(s²+4)

2s^{3}+s^{2}+8s+6=s³(A+C)+s²(B+D)+s(A+4C)+(B+4D)

We solve the equation system:

A+C=2

B+D=1

A+4C=8

B+4D=6

The solutions are:

A=0 ; B= -2/3 ; C=2 ; D=5/3

So,

Y(s)=\frac{-\frac{2}{3} }{s^{2}+4} +\frac{2s+\frac{5}{3} }{s^{2}+1}

Y(s)=-\frac{1}{3} \frac{2}{s^{2}+4} +2\frac{s }{s^{2}+1}+\frac{5}{3}\frac{1}{s^{2}+1}

By using the inverse of the Laplace transform:

ℒ⁻¹[Y(s)]=ℒ⁻¹[-\frac{1}{3} \frac{2}{s^{2}+4}]-ℒ⁻¹[2\frac{s }{s^{2}+1}]+ℒ⁻¹[\frac{5}{3}\frac{1}{s^{2}+1}]

y(t)= - \frac{1}{3} Sin(2t)+2 Cos(t)+\frac{5}{3} Sin(t)

3 0
3 years ago
Other questions:
  • What is the similarity ratio of a cube with volume 1,728m3 to a cube with volume 19,683m3?
    6·1 answer
  • Find the 74th term of the arithmetic sequence -8, 0, 8
    14·1 answer
  • A person who is six feet tall casts a 3-foot-long shadow. A nearby pine tree casts a 15-foot-long shadow.What is the height hh o
    9·2 answers
  • The rectangle in the following figure has a base that equals three times its height. Find an expression for the rectangle's peri
    6·1 answer
  • Calculate the value of B in the triangle below.
    12·1 answer
  • steve deposits $1250 in an account paying 3.4% annual interest compounded continously. how long will it take for the account bal
    11·1 answer
  • If f(x) = -3x-5 and g(x)=4x-2, find (f-g)(x)
    6·2 answers
  • (2+4i) + (9+10i) = (2+9) + (4i+10i)
    11·1 answer
  • 2/3 x 27 ........................
    9·2 answers
  • The function has three factors. Two of these factors
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!