mol CO₂ = 9.6
mol N₂ = 4.8
mol O₂ = 0.8
mol H₂O = 8
<h3>Further explanation</h3>
Reaction
4C₃H₅O₉N₃ → 12CO₂ + 6N₂ + O₂ + 10H₂O
mol CO₂
mol N₂
mol O₂
mol H₂O
Answer:
Masses of bromobenzene molecular ions will occur at 156 and 158 m/z.
Explanation:
The molecular ion peak is the signal in the mass spectrum of a compound that represents the molecular ion (denoted as M). Compounds that are composed of atoms having abundant isotope also shows M +1 and M+2 peaks (depending on the isotope).
In the given bromobenzene compound, an atom of bromine is present. The two isotopes with considerable relative abundance of Br are 79Br and 81Br with a difference of two units in their mass. This means that two molecular ion peaks with a difference of two units will appear in the mass spectrum. The mass of the whole compound is 156 amu. Hence, the molecular ion peaks will appear at 156 m/z and 158 m/z due to the two isotopes of bromine.
Answer:
2.4 g
Explanation:
Step 1: Given data
- Initial pressure (P₁): 755 torr
- Final pressure (P₂): 1.87 atm
Step 2: Convert "P₁" to atm
We will use the conversion factor 1 atm = 760 torr.
755 torr × 1 atm/760 torr = 0.993 atm
Step 3: Convert "T" to K
We will use the following expression.
K = °C + 273.15
K = 25°C + 273.15 = 298 K
Step 4: Calculate the initial number of moles of He
We will use the ideal gas equation.
P₁ × V = n₁ × R × T
n₁ = P₁ × V/R × T
n₁ = 0.993 atm × 16.8 L/(0.0821 atm.L/mol.K) × 298 K
n₁ = 0.682 mol
Step 5: Calculate the final number of moles of He
We will use the ideal gas equation.
P₂ × V = n₂ × R × T
n₂ = P₂ × V/R × T
n₂ = 1.87 atm × 16.8 L/(0.0821 atm.L/mol.K) × 298 K
n₂ = 1.28 mol
Step 6: Calculate the moles of He added
n = n₂ - n₁
n = 1.28 mol - 0.682 mol
n = 0.60 mol
Step 7: Convert "n" to mass
The molar mass of He is 4.00 g/mol
0.60 mol × 4.00 g/mol = 2.4 g
