Answer:
Q 3 = lightning
Q 4 = False because there is also a fourth state of matter which is called plasma.
Q 5 = most of the matter in universe is made up of plasma.
Explanation:
Plasma:
" The ionized gaseous mixture consist of atoms, ions and electrons is called plasma"
The plasma was first time identified by William Crookes in 1879. More than 99% universe matter is consist of plasma.
It is the fourth state of matter, the other three are solid, gas and liquid. The most of matter in the universe is plasma. When heat is supplied to the atoms, they gain energy the electrons in atom thus escape from the atom by gaining the energy and create the positive charge. Thus ions are formed. When heat is constantly supplied, the ionization process continue to take place and produce large number of positive charges, free electrons but some atoms not get ionized and remain neutral. Thus a cloud of free electrons , positive charge and neutral atoms is formed which is called plasma.
Examples:
The shining stars, lightning bolts, fluorescent light, flames, electrical current which passes through neon gas are some examples of plasma.
Answer:
<em>The number of electrons in the outermost shell of an element is represented in the periodic table as the group number that element is situated in. ... the number of electrons in all shells of an element is represented in the periodic table as the element's atomic number.</em>
Explanation:
<em>thatdummyemily </em>
<em>hope this helps srry if it doesn't tho, but if it does help can u plz mark me brainlist</em>
Try 22.4 and see if that works
Answer:
See explanation
Explanation:
Dilution law= C1V1=C2V2.
Where C is the concentration in mol per dm cube and V= volume in dm cube.
From the questions the parameters given are; V= 42.5ZmL, concentration or molarity of HCl= 0.193M and the molarity of KOH = 0.125M.
(a). At 0mL where the base KOH has not been added yet.
Moles of HCl = molarity × volume.
Moles of HCl = 0.193 × 42.5/1000
Moles of HCl= 0.00820205
pH=- log 0.0082025
pH= 2.086
Approximately, pH=2.1.
(b). At 3mL of 0.125M KOH
3/1000 × 0.125 mol/L
= 0.003L× 0.125 M
= 0.000375 moles KOH
Determining the number of moles of HCl, we have;
42.5/1000 × 0.193 mol/L
= 0.0082025
Final volume= 3mL+42.5mL= 45.5 ml
Final[HCl] = 0.0082025 - 0.000375 = 0.0078275.
Therefore, 0.0078275/ 0.0455
= 0.1720
pH= -log 0.1720
pH= 0.76.
(c). 5mL of 0.125M KOH
5/1000 × 0.125
= 0.005×0.125
= 0.000625 mol KOH
42.5/1000 × 0.193 mol/L
= 0.0082025 mol
Final volume= 5mL + 42.5= 47.5 mL.
0.0082025-0.000625= 0.0076
Final [HCl] = 0.0076/0.0475
= 0.16
pH= -log 0.16
pH= 0.79.
