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Harlamova29_29 [7]
3 years ago
5

(9,-9), (13,-3) djfjfifugjfjjdjd​

Mathematics
1 answer:
kondaur [170]3 years ago
4 0

Answer:

it would be in 2nd quadrant

Step-by-step explanation:

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Help ASAP!! This one's is difficult for me to understand!! Help me please!
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Answer:

Ok so im in 7thgrade so ima try to help answer is x= 8x9

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Use Julia’s work and finish finding the areas of the faces what is the surface area of the rectangular pyramid
hoa [83]

Answer:

The surface area of the rectangular pyramid is SA=109.50\ m^{2}

Step-by-step explanation:

we know that

The surface area of the rectangular prism is equal to the area of the rectangular base plus the area of the four triangular faces

so

SA=(8)(5)+2[14.75]+2[\frac{1}{2}(8)(5)]

SA=40+29.50+40

SA=109.50\ m^{2}

6 0
3 years ago
The Empire State Building weighs about 7.3×108pounds. The One World Trade Center building weighs about 88,200,000 pounds. What i
In-s [12.5K]

Answer:

8.182X10^8 $pounds

a=8.182 and b=8

Step-by-step explanation:

Weight of the Empire State Building =7.3X 10^8 pounds.

Weight of the One World Trade Center building= 88,200,000 pounds.

=8.82 X 10^7

The addition of the two:

=7.3X 10^8+8.82 X 10^7\\$To make it easier to add, express both as powers of 8\\=7.3X 10^8+0.882 X 10^8\\=(7.3+0.882)X10^8\\=8.182X10^8 $ pounds

Comparing with the form: aX10^b

a=8.182 and b=8

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A. 60 degrees is the answer
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