Answer:
The answer is the first graph.
Step-by-step explanation:
I did it on edge. I got it wrong the first time because I used an answer from this question. Because of that, I reported it. Now I have the correct answer lol.
Answer:
New mean length of these 17 people=11.62
Step-by-step explanation:
<em>Step 1: Determine the total length of children's fingers</em>
L=l×n
where;
L=total length (cm)
l=mean length (cm)
n=number of children
replacing;
L=6.7×6=40.2 cm
The total children's fingers length=40.2 cm
<em>Step 2: Determine the total length of adults fingers</em>
total length of adults fingers=mean length of adults fingers×number of adults
where;
mean length of adults=14.3
number of adults=11
replacing;
total length of adults fingers=(14.3×11)=157.3 cm
<em>Step 3: Determine the new mean length</em>
new mean length=total length of adults and children fingers/number of adults and children
where;
total length of adults and children fingers=157.3+40.2=197.5 cm
number of adults and children=11+6=17
replacing;
new mean length=197.5/17=11.62
Find the surface area of what?
<h3>
Answer: 8/25</h3>
=======================================================
Explanation:
In a standard deck, there are 52 cards.
If this deck is missing the queen of hearts and 2 of clubs, then we really have 52-2 = 50 cards in the deck.
There are 4 aces and 13 spades. Those values add to 4+13 = 17, but we need to subtract off 1 to account for the ace of spades counted twice. We have 17-1 = 16 cards that are either an ace, a spade, or both.
Or you can think of it like saying 13 spades + 1 ace of hearts + 1 ace of diamonds + 1 ace of clubs = 16 cards total.
-----------------
The event space has A = 16 cards in it, while the sample space has B = 50 cards.
The probability we're after is A/B = 16/50 = 8/25
Answer:
Multiply row 1 by 
.
Step-by-step explanation:
The augmented matrix of the system of linear equation is described below:
![\left[\begin{array}{cccc}2&1&-1&-8\\0&2&3&-6\\-\frac{1}{2} &1&1&-4\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D2%261%26-1%26-8%5C%5C0%262%263%26-6%5C%5C-%5Cfrac%7B1%7D%7B2%7D%20%261%261%26-4%5Cend%7Barray%7D%5Cright%5D)
Where 
, if we need to create 
, we need to multiply row 1 by , that is to say:
![\left[\begin{array}{cccc}1&\frac{1}{2} &-\frac{1}{2} &-4\\0&2&3&-6\\-\frac{1}{2} &1&1&-4\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%26%5Cfrac%7B1%7D%7B2%7D%20%26-%5Cfrac%7B1%7D%7B2%7D%20%26-4%5C%5C0%262%263%26-6%5C%5C-%5Cfrac%7B1%7D%7B2%7D%20%261%261%26-4%5Cend%7Barray%7D%5Cright%5D)
Hence, the correct answer is: Multiply row 1 by .
