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Rudik [331]
4 years ago
9

In a deck of cards with 52 cards and 4 suits, what is the probability of getting an ace?

Mathematics
2 answers:
DedPeter [7]4 years ago
7 0

The probability of picking up an ace in a 52 card deck, where there are 4 aces is 4/54 (simplify to 2/27).

Katarina [22]4 years ago
6 0

The probability of getting a ace is 8/52

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Stacy decided that she would start doing sit ups every day. Her plan each day was to do twice as many sit ups as she had done th
Whitepunk [10]

Answer:

Day five= 32 sit ups

Step-by-step explanation:

Day 1= 2 sit ups

Day 2= 4 sit ups

Day 3= 8 sit ups

Day 4= 16 sit ups

Day 5= 32 sit ups

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3 years ago
Find the measure of CDE
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Step-by-step explanation:

Here,

CDE+27+103+50+35=360(BEING THE SUM OF PIE CHART

CDE+215=360

CDE=360-215

CDE=145

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3 years ago
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3 years ago
how many ways can Aileen choose 2 pizza toppings from a menu of 19 toppings if each topping can only be chosen one​
alexdok [17]

Answer:

There are 342 different combinations.

Step-by-step explanation:

Ok, Aileen is choosing toppings for a pizza.

She can choose two.

There are 19 options that can be chosen once.

The first thing we need to do, is find all the "selections".

Here we have two selections:

Topping number 1

Topping number 2.

Now we need to find the number of options for each one of these selections:

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Topping number 2:  Here we have 18 options (because one was already taken in the previous selection)

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7 0
3 years ago
You have $7000 with which to build a rectangular enclosure with fencing. The fencing material costs $30 per meter. You also want
Arlecino [84]

Answer:

1857.12 square meters

Step-by-step explanation:

Let L be the length of the rectangle and 'W' be the width

Perimeter = 2L + 2W + 2W

The fencing material costs $30 per meter.

The material for the partitions costs $25 per meter

cost=30(2L + 2W) +25( 2W)\\60L+60W+50W\\60L +110W

7000=60L+110W

Solve for L

7000=60L+110W\\7000-110W= 60L\\L=\frac{700}{6} -\frac{11}{6} W

Area = length times width

( \frac{700}{6} -\frac{11}{6} W)(W)\\A(W)=\frac{700}{6}W -\frac{11}{6} W^2

Now take derivative and set it =0

A(W)=\frac{700}{6}W -\frac{11}{6} W^2\\A'(W)=\frac{700}{6} -\frac{22}{6} W

set the derivative =0  and solve for W

0=\frac{700}{6} -\frac{22}{6} W\\\frac{700}{6}=\frac{22}{6} W\\W= 31.8

So width = 31.8 that gives maximum area

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Area = length  \cdot width = 31.8 \cdot 58.4= 1857.12 square meter

4 0
3 years ago
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