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wel
3 years ago
10

HELP PLEASEEEEEEEEEE​

Mathematics
1 answer:
defon3 years ago
5 0

Answer:

x=8

Step-by-step explanation:

because x is a pronoun in the laws of math. Hope this helps! lol

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A chicken weighs t lbs. It needs to be cooked for 20 minutes per lb plus an extra 15 minutes. What is the total cooking time? Is
Nostrana [21]

Answer:

Total cooking time = 20t + 15

The expression 15t + 20 is wrong.

Step-by-step explanation:

weight of chicken = t lbs

cook time per lb = 20 minutes

This means that:

1 lb weight requires a cooking time of 20 minutes

1 lb = 20 minutes

∴ t lbs = 20 × t = 20t minutes.

We were also told that each chicken required an extra cooking time of 15 minutes, in addition to the total cooking time due to the weight. Therefore, the total cooking time is calculated thus:

Total cooking time = cooking time due to weight + 15 minutes

Total cooking time = 20t + 15

Hence the expression 15t + 20 is wrong, due to the explanation given above.

8 0
3 years ago
What is the approximate circumference of a circle with a radius of 8.5 meters? Use π ≈ 3.14.
Simora [160]
The answer is 11.16 hope  i
helped
3 0
3 years ago
Find the exact value of cos(sin^-1(-5/13))
son4ous [18]

bearing in mind that the hypotenuse is never negative, since it's just a distance unit, so if an angle has a sine ratio of -(5/13) the negative must be the numerator, namely -5/13.

\bf cos\left[ sin^{-1}\left( -\cfrac{5}{13} \right) \right] \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{then we can say that}~\hfill }{sin^{-1}\left( -\cfrac{5}{13} \right)\implies \theta }\qquad \qquad \stackrel{\textit{therefore then}~\hfill }{sin(\theta )=\cfrac{\stackrel{opposite}{-5}}{\stackrel{hypotenuse}{13}}}\impliedby \textit{let's find the \underline{adjacent}}

\bf \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{13^2-(-5)^2}=a\implies \pm\sqrt{144}=a\implies \pm 12=a \\\\[-0.35em] ~\dotfill\\\\ cos\left[ sin^{-1}\left( -\cfrac{5}{13} \right) \right]\implies cos(\theta )=\cfrac{\stackrel{adjacent}{\pm 12}}{13}

le's bear in mind that the sine is negative on both the III and IV Quadrants, so both angles are feasible for this sine and therefore, for the III Quadrant we'd have a negative cosine, and for the IV Quadrant we'd have a positive cosine.

8 0
3 years ago
3x-9x+6=20-3x+4x Please answer.
fomenos
I gotchu.
<span>3x-9x+6=20-3x+4x
Combine like terms.
-6x+6=20+x
Bring x over to the left side.
-x            -x
-7x+6=20
bring 6 to the right side.
     -6   -6
-7x=14
Divide -7 on both sides to isolate x.
x= -2

CHECK
</span><span>3x-9x+6=20-3x+4x
-6(-2)+6=20+(-2)
18=18 
ANSWER: x= -2</span>
6 0
3 years ago
Graph the system of equations. { x−y=6 4x+y=4 Use the Line tool to graph the lines.
lapo4ka [179]
The answer would be that the dot falls on the point (0,4)

8 0
3 years ago
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