F is proportional to 1/x^2
distance = x
A reduction of 25 percent = 0.75x
Let’s put this in place of x
F = 1/(0.75x)^2
And simplify
F = 1/0.5625x^2
So you need to find the percentage increase from 1/x^2 to 1/0.5625x^2
So what does 1/x^2 multiply by to give 1/0.5625x^2
Written as an equation it is y/x^2 = 1/0.5625x^2
Multiply both sides by x^2
y = 1/0.5625
y = 1.778 (rounded to 3 decimal points)
So the decimal multiplier is 1.778 and so the percent increase is approximately 77.8%
Answer:
Third option.
Step-by-step explanation:
You need to remember that the formula used to calculate the arc lenght is:
Where "r" is the radius and "C" is the central angle in radians.
You need to solve for "C":
You know the radius and the arc lenght, therefore, you can substitute values to calculate the central angle in radians. Therefore, this is:
Answer:
trapezium that is the answet
<u>Complete Question:</u>
Janeel has a 10 inch by 12 inch photograph. She wants to scan the photograph, then reduce the results by the same amount in each dimension to post on her Web site. Janeel wants the area of the image to be one eight of the original photograph. Write an equation to represent the area of the reduced image. Find the dimensions of the reduced image.
<u>Correct Answer:</u>
A)
B) Dimensions are : Length = 10-x = 3 inch , Breadth = 12-x = 5 inch
<u>Step-by-step explanation:</u>
a. Write an equation to represent the area of the reduced image.
Let the reduced dimensions is by x , So the new dimensions are
According to question , Area of new image is :
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So the equation will be :
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b. Find the dimensions of the reduced image
Let's solve :
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By Quadratic formula :
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x = 15 is rejected ! as 15 > 10 ! Side can't be negative
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Therefore, Dimensions are : Length = 10-x = 3 inch , Breadth = 12-x = 5 inch
Answer:
commutative property of multiplication
Step-by-step explanation: