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2 years ago

10

Who can me with this Help????

1 answer:

Marysya12 [62]2 years ago

8 0

Answer:

Step-by-step explanation:

what is the broken image part supposed to say?

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For the given decimal −0.009, find the two integers closest to it.

asambeis [7]

Answer:

The two integers closest to -0.009 are -1 and 0

Step-by-step explanation:

we have the number

$-0.009$

Convert to fraction number

$-0.009=-\frac{9}{1,000}$

In a number line

$-\frac{1,000}{1,000} < -\frac{9}{1,000}$

Remember that

$-\frac{1,000}{1,000}=-1\\\frac{0}{1,000}=0$

so

$-1 < -\frac{9}{1,000}$

therefore

The two integers closest to -0.009 are -1 and 0

7 0

3 years ago

What is the product of a fraction multiplied by its multiplicative inverse? Justify your answer with an example

Lina20 [59]

I believe the answer will always be one.
Heres an example: 5/8 • 8/5 = 1

8 0

2 years ago

If h(x)=(fog)(x) and h(x)=³√x+3, find g(x) if f(x) =³√x+2

ipn [44]

Answer:

$g(x)=x+1$

The problem:

Find $g(x)$ if $h(x)=(f \circ g)(x)$ ,

$h(x)=\sqrt[3]{x+3}$ , and

$f(x)=\sqrt[3]{x+2}$ .

Step-by-step explanation:

$h(x)=(f \circ g)(x)$

$h(x)=f(g(x))$

Replace $x$ in $f(x)=\sqrt[3]{x+2}$ with $g(x)$ since we are asked to find $f(g(x))$ :

$\sqrt[3]{x+3}=\sqrt[3]{g(x)+2}$

$\sqrt[3]{x+1+2}=\sqrt[3]{g(x)+2}$

This implies that $x+1=g(x)$

Let's check:

$(f \circ g)(x)$

$f(g(x))$

$f(x+1)$

$\sqrt[3]{(x+1)+2}$

$\sqrt[3]{x+1+2}$

$\sqrt[3]{x+3}$ which is the required result for $h(x)$ .

6 0

2 years ago

Rules for multiplying and dividing by 1 and 0

liubo4ka [24]

Mutiplying: the product is always 0

7 0

3 years ago

Read 2 more answers

Please helpppppppppppppppp

Zina [86]

Answer:

29520728184915396206153835295

3 0

2 years ago