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3 years ago

Examine the diagram.

Mathematics

2 answers:

Nesterboy [21]3 years ago

3 0

Answer:

the supplement of, 117 degrees.

Step-by-step explanation:

got it right endginuity 2021

inna [77]3 years ago

3 0

Answer: The supplement of , 117 degrees

Step-by-step explanation: i hope this helps! :)

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Ali salary is increased from 2600 to 3000 . How much is percentage increase

nadezda [96]

Answer:

15.3 %

Step-by-step explanation:

400 / 2600 x 100 = 15.3 %

I hope im right!!

8 0

3 years ago

Read 2 more answers

Andres company manufactures rectangular storage sheds decisions are made with aluminum side panels that measure 8 feet 10 feet 1

UkoKoshka [18]

We know that

The formula for combinations is<span>
C=n!/[(n-r)!*r!]
where
n is the total number of objects you choose from
r is the number that you choose to arrange

in this problem
n=4 </span>aluminum side panels measures

r=2 aluminum side panels measures

<span> C=4!/[(4-2)!*2!]-----> C=4!/[2!*2!]---> (4*3*2!)/(2!*2*1)
C</span>=6

1) 8 ft x 10 ft

2) 8 ft x 12 ft

3)8 ft x 15 ft

4) 10 ft x 12 ft

5) 10ft x 15 ft

6) 12 ft x 15 ft

additionally, we have each measure with itself

7) 8 ft x 8 ft

8) 10 ft x 10 ft

9) 12 ft x 12 ft

10) 15 ftx 15 ft

the answer is

10 possible sets

4 0

4 years ago

A Common Measure of Student Achievement, The National Assessment of Educational Progress (NAEP) is the only assessment that meas

vlada-n [284]

Answer:

a) By the central limit theorem we know that if the random variable X="quantitative scores for young women", and we know that this distribution is normal.

$X \sim N(\mu, \sigma=60)$

And we are interested on the distribution for the sample mean $\bar X$ , we know that distribution for the sample mean is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And with that we have the assumptions required to apply the normal distribution to create the confidence interval since the distribution for $\bar X$ is normal.

b) $270.283\leq \mu \leq 279.717$

c) We are confident (99%) that the true mean for the quantitative scores for young women is between (270.283;3279.717)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=275$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

$\sigma=60$ represent the population standard deviation

n=1077 represent the sample size

Part a

By the central limit theorem we know that if the random variable X="quantitative scores for young women", and we know that this distribution is normal.

$X \sim N(\mu, \sigma=60)$

And we are interested on the distribution for the sample mean $\bar X$ , we know that distribution for the sample mean is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And with that we have the assumptions required to apply the normal distribution to create the confidence interval since the distribution for $\bar X$ is normal.

Part b

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

Since the Confidence is 0.99 or 99%, the value of $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.005,0,1)".And we see that $z_{\alpha/2}=2.58$