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Llana [10]
2 years ago
6

Please i need help!

Mathematics
1 answer:
inysia [295]2 years ago
3 0
I think it’s the 3rd one
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3125x=−62 value of x.
Papessa [141]

Answer:

x= -0.01984

Step-by-step explanation:

You divide both sides by 3125 to get x alone.

You get x=-0.01984

Hope this helps!

5 0
2 years ago
Jared drove a distance of 165 miles to billings last weekend, which used 11 gallons of gas. How many gallons of gas will he need
blondinia [14]

Answer:

8550

Step-by-step explanation:

1. you need to figure out how many time 11 goes into 165 which is 15 then you need to get the 15 and multiply it by 570.

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3 years ago
Which is a needed step to prove that AABF = AEDG?
Gwar [14]

Answer: helllloooooooooooooo000000oooo

Step-by-step explanation:

7 0
3 years ago
Expand (n+5)*2 by using the perfect square pattern
mario62 [17]
N^2 + 25 if you mean *2 is squared.
8 0
3 years ago
If f(x)=2−x12 and g(x)=x2−9, what is the domain of g(x)÷f(x)?
Keith_Richards [23]
\bf \begin{cases}
f(x)=2-x^{12}\\
g(x)=x^2-9\\
g(x)\div f(x)=\frac{g(x)}{f(x)}
\end{cases}\implies \cfrac{x^2-9}{2-x^{12}}

now, for a rational expression, the domain, or "values that x can safely take", applies to the denominator NOT becoming 0, because if the denominator is 0, then the rational turns to undefined.

now, what value of "x" makes this denominator turn to 0, let's check by setting it to 0 then.

\bf 2-x^{12}=0\implies 2=x^{12}\implies \pm\sqrt[12]{2}=x\\\\
-------------------------------\\\\
\cfrac{x^2-9}{2-x^{12}}\qquad \boxed{x=\pm \sqrt[12]{2}}\qquad \cfrac{x^2-9}{2-(\pm\sqrt[12]{2})^{12}}\implies \cfrac{x^2-9}{2-\boxed{2}}\implies \stackrel{und efined}{\cfrac{x^2-9}{0}}

so, the domain is all real numbers EXCEPT that one.
4 0
3 years ago
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