Please i need help!

Ms. Perkins has a bag of candy with 30 pieces. She gave away 1/5 of the pieces to her students. How many pieces does she have le

fgiga [73]

Ms. Perkins will have 24 pieces of candy left, because 30 ÷ 5 = 6. So there for 1/5 is equal to 6 pieces of candy.

6 0

3 years ago

A recipe for sugar cookies requires 2 cups of flour for every 2/3 cups of sugar. At this rate, how many cups of sugar should be

Flura [38]

To get 2 to 5, you multiply 2 by 2.5. do the same to 2/3 to get your answer. 2/3 times 2.5 = 2/3 times 5/2 equals 10/6 or 5/3 cups of sugar (1 and 2/3 cups of sugar) i believe

8 0

3 years ago

Can someone pls help need it ASAP and can you pls explain in full detail how to do it

GenaCL600 [577]

Answer:

x= 1 , y=4

Step-by-step explanation:

x-y= -3 => Equation 1

x+5y= 21 => Equation 2

Substitution Method:

Substitute Equation 1=>

x=y-3 <= Equation 3

Put x=y-3 in Equation 2:

x+5y=21

( y-3)+5y=21

y-3+5y=21

6y-3=21

6y=21+3

6y=24

y=24÷6

y=4

Put y=4 in Equation 1:

x-y= -3

x-4=-3

x=4-3

x=1

Hope this helps :)

8 0

2 years ago

Read 2 more answers

A circle has the order pairs (-1, 2) (0, 1) (-2, -1) what is the equation . Show your work.

olga55 [171]

We know that:

$(x-a)^2+(y-b)^2=r^2$

is an equation of a circle.

When we substitute x and y (from the pairs we have), we'll get a system of equations:

$\begin{cases}(-1-a)^2+(2-b)^2=r^2\\(0-a)^2+(1-b)^2=r^2\\(-2-a)^2+(-1-b)^2=r^2\end{cases}$

and all we have to do is solve it for a, b and r.

There will be:

$\begin{cases}(-1-a)^2+(2-b)^2=r^2\\(0-a)^2+(1-b)^2=r^2\\(-2-a)^2+(-1-b)^2=r^2\end{cases}\\\\\\
\begin{cases}1+2a+a^2+4-4b+b^2=r^2\\a^2+1-2b+b^2=r^2\\4+4a+a^2+1+2b+b^2=r^2\end{cases}\\\\\\
\begin{cases}a^2+b^2+2a-4b+5=r^2\\a^2+b^2-2b+1=r^2\\a^2+b^2+4a+2b+5=r^2\end{cases}\\\\\\
$

From equations (II) and (III) we have:

$\begin{cases}a^2+b^2-2b+1=r^2\\a^2+b^2+4a+2b+5=r^2\end{cases}\\--------------(-)\\\\a^2+b^2-2b+1-a^2-b^2-4a-2b-5=r^2-r^2\\\\-4a-4b-4=0\qquad|:(-4)\\\\\boxed{-a-b-1=0}$

and from (I) and (II):

$\begin{cases}a^2+b^2+2a-4b+5=r^2\\a^2+b^2-2b+1=r^2\end{cases}\\--------------(-)\\\\a^2+b^2+2a-4b+5-a^2-b^2+2b-1=r^2-r^2\\\\2a-2b+4=0\qquad|:2\\\\\boxed{a-b+2=0}$

Now we can easly calculate a and b:

$\begin{cases}-a-b-1=0\\a-b+2=0\end{cases}\\--------(+)\\\\-a-b-1+a-b+2=0+0\\\\-2b+1=0\\\\-2b=-1\qquad|:(-2)\\\\\boxed{b=\frac{1}{2}}\\\\\\\\a-b+2=0\\\\\\a-\dfrac{1}{2}+2=0\\\\\\a+\dfrac{3}{2}=0\\\\\\\boxed{a=-\frac{3}{2}}$

Finally we calculate $r^2$ :

$a^2+b^2-2b+1=r^2\\\\\\\left(-\dfrac{3}{2}\right)^2+\left(\dfrac{1}{2}\right)^2-2\cdot\dfrac{1}{2}+1=r^2\\\\\\\dfrac{9}{4}+\dfrac{1}{4}-1+1=r^2\\\\\\\dfrac{10}{4}=r^2\\\\\\\boxed{r^2=\frac{5}{2}}$

And the equation of the circle is:

$(x-a)^2+(y-b)^2=r^2\\\\\\\left(x-\left(-\dfrac{3}{2}\right)\right)^2+\left(y-\dfrac{1}{2}\right)^2=\dfrac{5}{2}\\\\\\\boxed{\left(x+\dfrac{3}{2}\right)^2+\left(y-\dfrac{1}{2}\right)^2=\dfrac{5}{2}}$

7 0

3 years ago

Louis bought a giant sub sandwich for the party. He wants to cut into 6-inch sections. If the sandwich is 18.25 feet, how many s

Lynna [10]

36.5
He’d have 36, 6 in sandwiches and a 3 inch section left
Explanation:
Take 18.25 and multiply by 12 which gives you 219. The amount of inches in the sandwich. Then divide 219 by 6 and you get 36.5

5 0

2 years ago