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3 years ago

I ONLY need HELP on number 3 what does it mean for me to do?? Thank You All in Advance!!!!!!

Mathematics

1 answer:

Sladkaya [172]3 years ago

8 0

3(5+7) is the problem you are looking at. To figure it out, you can use properties. On the right side of the equals sign, it shows a property you can use to do the problem. In this case, they are distributing.

You might be interested in

Find the slope of the line passing through (-9,3), (-3,-5)

egoroff_w [7]

Answer:

-4/3

Step-by-step explanation:

Slope: (y2-y1)/(x2-x1)

(-5-3)/(-3+9) = -8/6 = -4/3

The slope is -4/3

6 0

3 years ago

Write an explicit formula for an, the nth term of the sequence 19,24,29

o-na [289]

Answer:

explicit formula for an, the nth term of the sequence 19,24,29

$a_1=19 ; \ a_n=a_{n-1}+5$

Step-by-step explanation:

We need to Write an explicit formula for an, the nth term of the sequence 19,24,29

In the sequence the First term a₁= 19

Common Difference d= 5

The Formula used for explicit formula is: $a_1=First \ term ; \ a_n=a_{n-1}+d$

Where d is common difference and n is nth term of sequence.

So, explicit formula for an, the nth term of the sequence 19,24,29

$a_1=19 ; \ a_n=a_{n-1}+5$

3 0

3 years ago

A rock is thrown at 0 seconds from a height of 6 feet. If the parabola representing the height as a function of time has a verte

Korolek [52]

Answer:

The correct option is;

The graph will have a height of 6 feet at 16 seconds

Step-by-step explanation:

The given parameters are;

The start time for throwing the rock = 0 s

The height from which the rock is thrown = 6 ft

The vertex of the parabola = 8 seconds

Given that the vertex is the axis of symmetry, then the time it takes the rock to reach the vertex (8 seconds) from the point (0, 6) will be the same time it takes the rock to reach the point on the other side of the parabola at the same 6 feet which will then have coordinates (8 + 8, 6) or (16, 6) which will be 6 feet in 16 seconds.

3 0

3 years ago

A student's course grade is based on one midterm that counts as 15% of his final grade, one class project that counts as 15% of

kow [346]

Answer:

Overall final score = 77.75% ; Grade = C.

Step-by-step explanation:

The approach to solve this question is to realize that the marks have to be converted into the respective percentages of the whole course. This means that the marks of all the components have to be normalized according to the grading breakdown.

Project Marks = 97/100. Weightage = 15%. So 97*15/100 = 14.55/15.

This means that the student received 14.55 marks in the project out of 15.

Similarly for other components:

Mid-Term Marks = 83/100. Weightage = 15%. So 83*15/100 = 12.45/15.

Homework Marks = 82/100. Weightage = 35%. So 82*35/100 = 28.7/35.

Finals Marks = 63/100. Weightage = 35%. So 63*35/100 = 22.05/35.

After the conversion process, add up the normalized marks, which are now acting as the percentages earned in all the components.

Aggregate Percentage = 14.55 + 12.45 + 28.7 + 22.05 = 77.75%.

According to the grade scale, the student receives a C because 70 is less than 77.75 and 77.75 is less than 80.

Summarizing, the student receives a C at 77.75%!!!

7 0

3 years ago

PLEASE HELP

iren [92.7K]

After plotting the data from the table, with the number of times sick per year as a function of the number of apples eaten per week, I can conclude that there is no definite correlation between the two variables. This is because the data points do not have a good fit with any trend, meaning the R-squared value is low. Thus, the number of apples eaten per week has no significant effect on the number of times the people listed get sick per year.

6 0

3 years ago