The answer is d.
First you have to divide 160/ 1/4. So you would do 160/1 divided by 1/4. Because of keep, change and flip. (k.c.f) you would keep 160/1, change the division sign, then flip 1/4 to 4/1. Then you multiply 160/1*4/1. Then you would get 640. Hope this helped.
Answer:
D. This sequence is a function because each output (even terms in sequence) maps to one input (odd terms in sequence).
Step-by-step explanation:
0, 10, 2, 12, 4, 14, 6, 16, 8, 18, 10, 20
he startes with $0 he gits his first allowance wich is $10, he spends $8 and saves $2. he gits anuther $10 and the remaning $2 is $12 he spends $8 he has $4 gits anuther $10 and the remaning $4 is $14 he spends $8 he has $6 he gits anuther $10 and the remaning $6 is $16 he spends $8 he has $8 he gits anuther $10 and the remaning $8 is $18 he spends $8 he has $10 he gits anuther $10 and the remaning $10 is $20.
hope this helped
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Answer:
The radius of a circumcircle of an equilateral triangle is equal to (a / √3), where ‘a’ is the length of the side of equilateral triangle.
Circle Radius = 16 / sq root (3)
Circle Radius = 9.237604307
Circle Area = PI * radius ^ 2
Circle Area = PI * 85.3333333333
Circle Area = 268.083
Equilateral Triangle area = side^2 * sq root (3) / 4
Equilateral Triangle area = 16^2 * 0.4330127019
Equilateral Triangle area = 110.85
Shaded region = 268.083 - 110.85
Shaded region = 157.233
Step-by-step explanation:
Given a right angle triangle
The length of the legs are 4 and 7
we will find the hypotenuse using the Pythagorean theorem
So,
![\begin{gathered} h^2=7^2+4^2=49+16=65 \\ h=\sqrt[]{65}\approx8.062 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20h%5E2%3D7%5E2%2B4%5E2%3D49%2B16%3D65%20%5C%5C%20h%3D%5Csqrt%5B%5D%7B65%7D%5Capprox8.062%20%5Cend%7Bgathered%7D)
Rounding to the nearest tenth
So, the answer is the length of the third side = 8.1
To graph y=-7x-3, you're going to make your first coordinate at (-3,0) b/c that is your y-intercept and you will continuously move down 7 and right one.
To graph y=4, you will simply make a horizontal line through the to coordinate (4,0).
Hope that helped.
