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3 years ago

I need help with finding the GCF (greatest common factor) of 72,48

2 answers:

4 0

The factors of 72 are 1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36, and 72 .

The factors of 48 are 1, 2, 3, 4, 6, 8, 12, 16, 24, and 48 .

The factors common to both 72 and 48 are 1, 2, 3, 4, 6, 8, 12, and 24 .

The greatest one of those is 24 .

kirza4 [7]3 years ago

3 0

First, find all the factors of the two numbers (separately):
72: 1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36, and 72
48: 1, 2, 3, 4, 6, 8, 12, 16, 24, 48
The numbers in bold are factors of both 72 and 48.
Find the greatest one (out of the numbers in bold). 24 is the GCF.

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Step-by-step explanation:

Let $V_{2}. V_{3}. and\ V_{4}.$ be the volume of the cone.

Let d, r and h be the diameter, radius and height of the cone.

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$d_{1} = 20\ and\ h_{1}=12$

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$r_{4} = 11\ and\ h_{14}=9$

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Solution:

The volume of the cone is given below.

$V=\pi r^{2} \frac{h}{3}$ ----------------(1)

where: r is radius of the base of cone.

and h is height of the cone.

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$r_{1} = \frac{d_{1}}{2}$

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$r_{2} = \frac{d_{2}}{2}$

$r_{2} = \frac{18}{2}=9\ units$

$V_{2}=\pi (r_{2})^{2} \frac{h_{2}}{3}$

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$V_{3}=\pi (r_{3})^{2} \frac{h_{3}}{3}$

$V_{3}=\pi (10)^{2} \frac{9}{3}$

$V_{3}=\pi\times 100\times 3$

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Similarly, for volume of the cone for $r_{4} = 11\ and\ h_{4}=9$

$V_{4}=\pi (r_{4})^{2} \frac{h_{4}}{3}$

$V_{4}=\pi (11)^{2} \frac{9}{3}$

$V_{4}=\pi\times 121\times 3$

$V_{4}=\pi\times 363$

$V_{4}=363\pi\ units^{3}$

So, the volume of the cone in ascending order.

$V_{2}=270\pi\ units^{3}$

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