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sertanlavr [38]
3 years ago
11

I need help with finding the GCF (greatest common factor) of 72,48

Mathematics
2 answers:
liubo4ka [24]3 years ago
4 0

The factors of  72  are  1,  2,  3,  4,  6,  8,  9,  12,  18,  24,  36, and  72 .

The factors of  48  are  1,  2,  3,  4,  6,  8,  12,  16,  24, and  48 .

The factors common to both  72  and  48  are  1,  2,  3,  4,  6,  8,  12, and  24 .

The greatest one of those is  <em>24 .</em> 


kirza4 [7]3 years ago
3 0
First, find all the factors of the two numbers (separately):
<span>72: 1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36, and 72
</span>48: <span>1, 2, 3, 4, 6, 8, 12, 16, 24, 48
The numbers in bold are factors of both 72 and 48.
Find the greatest one (out of the numbers in bold). 24 is the GCF.</span>
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V_{2}=270\pi\ units^{3}

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Step-by-step explanation:

Let V_{2}. V_{3}. and\  V_{4}. be the volume of the cone.

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Solution:

The volume of the cone is given below.

V=\pi r^{2} \frac{h}{3}----------------(1)

where: r is radius of the base of cone.

and h is height of the cone.

The volume of the cone for d_{1} = 20\ and\ h_{1}=12

r_{1} = \frac{d_{1}}{2}

r_{1} = \frac{20}{2}=10\ units

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r_{2} = \frac{d_{2}}{2}

r_{2} = \frac{18}{2}=9\ units

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Similarly, for volume of the cone for r_{3} = 10\ and\ h_{3}=9

V_{3}=\pi (r_{3})^{2} \frac{h_{3}}{3}

V_{3}=\pi (10)^{2} \frac{9}{3}

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Similarly, for volume of the cone for r_{4} = 11\ and\ h_{4}=9

V_{4}=\pi (r_{4})^{2} \frac{h_{4}}{3}

V_{4}=\pi (11)^{2} \frac{9}{3}

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V_{4}=\pi\times 363

V_{4}=363\pi\ units^{3}

So, the volume of the cone in ascending order.

V_{2}=270\pi\ units^{3}

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