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3 years ago

-6, 12 ,-24 ,48 what would be the next term in this sequence (help ASAP please )

Mathematics

1 answer:

patriot [66]3 years ago

3 0

The next term would be -96 ! your just adding the term twice and alternating it by making it a negative and a positive

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3 years ago

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Which expression is equivalent to sqrt8x^7y^8? assume x>0

Ilia_Sergeevich [38]

Answer:

$\sqrt{8x^7y^8$ $= 2x^3y^4 * \sqrt{2x}$

Step-by-step explanation:

Given

$\sqrt{8x^7y^8$

Required

Evaluate

$\sqrt{8x^7y^8$

Separate each factor with multiplication sign

$\sqrt{8*x^7*y^8$

Express 8 as 4 * 2 and $x^7$ as $x^6 * x$

$\sqrt{4 * 2 *x^6 * x*y^8$

Split each factor

$\sqrt{4} * \sqrt{2} *\sqrt{x^6} * \sqrt{x}*\sqrt{y^8}$

Evaluate $\sqrt4$

$2 * \sqrt{2} *\sqrt{x^6} * \sqrt{x}*\sqrt{y^8}$

Apply law of indices:

$2 * \sqrt{2} * x^{6*\frac{1}{2}} * \sqrt{x} * y^{8*\frac{1}{2}}$

$2 * \sqrt{2} * x^3 * \sqrt{x} * y^4$

Reorder

$2* x^3 * y^4 * \sqrt{2} * \sqrt{x}$

$2x^3y^4 * \sqrt{2} * \sqrt{x}$

$2x^3y^4 * \sqrt{2*x}$

$2x^3y^4 * \sqrt{2x}$

$2x^3y^4 \sqrt {2x$

Hence:

$\sqrt{8x^7y^8$ $= 2x^3y^4 * \sqrt{2x}$

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3 years ago

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3 years ago

What’s the inverse equation?

algol [13]

Answer:

The inverse is ((5-x)/4) ^ 1/3

Step-by-step explanation:

y = 5-4x^3

Exchange x and y

x = 5-4y^3

Subtract 5 from each side

x-5 =5-5-4y^3

x-5 = -4y^3

Divide each side by -4

(x-5)/ -4 = y^3

Take the cube root

((x-5)/ -4) ^ 1/3 = y^ 3 ^1/3

((5-x)/4) ^ 1/3 = y

The inverse is ((5-x)/4) ^ 1/3

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3 years ago

4u - 10 > -2 what is the answer

alexdok [17]

Answer:

14>-9

Step-by-step explanation:

hope it work U_U enjoy tho

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3 years ago