Answer:
The velocity of the car after the collision is -5.36 m/s
Step-by-step explanation:
An elastic collision is an encounter between two bodies in which the total kinetic energy of the two bodies remains the same.
let the following:
m₁ = mass of the car = 1400 kg
m₂ = mass of the truck = 3200 kg
u₁ = velocity of the car before collision = 13.7 m/s
u₂ = velocity of the truck before collision = 0 m/s
v₁ = velocity of the car after collision
v₂ = velocity of the truck after collision
v₁ = [ u₁ * (m₁ - m₂) + u₂ * 2m₂ ]/ (m₁ + m₂)
= [ 13.7 * (1400 - 3200) + 0 * 2 * 3200 ]/ (1400 + 3200)
= - 5.36 m/s
So, <u>the velocity of the car after the collision is -5.36 m/s</u>
Answer:
X = 2
Step-by-step explanation:
6(2) = 12
6 X 2 = 12
Answer: −10
Step-by-step explanation: 9^2−21/−6
81−21/−6
60/−6
−10
Answer:
Cost of a coffee is <u>$2.5</u> and cost of a latte is <u>$4.25.</u>
Step-by-step explanation:
Let cost of 1 coffee be 'c' and cost of 1 latte be 'l' dollars.
Given:
4 coffees and 12 lattes cost $61.
12 coffees and 7 lattes cost $59.75.
∵ 1 coffee cost =
∴ 4 coffees cost = and 12 coffee cost =
∵ 1 latte cost =
∴ 12 lattes cost = and 7 lattes cost =
Now, as per question:
Now, multiplying equation (1) by -3 and adding the result to equation (2). This gives,
Now, plug in the value of 'l' in equation 1 to solve for 'c'. This gives,
Therefore, cost of a coffee is $2.5 and cost of a latte is $4.25.