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lakkis [162]
3 years ago
10

Solve: what is 2730 ÷ 1.3 there is not a problem

Mathematics
2 answers:
vlabodo [156]3 years ago
7 0

Answer:

2100

Step-by-step explanation:

photoshop1234 [79]3 years ago
3 0

Answer: 2100

Step-by-step explanation: 2730 divied by 1.3 is 2100.

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Solve the quadratic equation -x^2=4
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A graphics designer is designing an advertising brochure for an art show. Each page of the brochure is rectangular with an area
Elena-2011 [213]

Answer:  The length of the loner side is 7 in. and the length of the shorter side is 6 in.

Step-by-step explanation:  Given that a graphics designer is designing an advertising brochure for an art show. Each page of the brochure is rectangular with an area of 42 in squared and a perimeter of 26 in.

We are to find the dimensions of the brochure.

Let l and b represents the lengths of the longer side and shorter side respectively of each page of the brochure.

Then, according to the given information, we have

l\times b=42~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

and

2(l+b)=26\\\\\Rightarrow l+b=13\\\\\Rightarrow l=13-b~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(ii)

Substituting the value of l from equation (ii) in equation (i), we get

(13-b)b=42\\\\\Rightarrow b^2-13b+42=0\\\\\Rightarrow b^2-6b-7b+42=0\\\\\Rightarrow (b-6)(b-7)=0\\\\\Rightarrow b-6=0,~~~b-7=0\\\\\Rightarrow b=6,7.

Since b is the length of the shorter side, so b = 6 in.

From equation (ii), we get

l=13-6=7.

Thus, the length of the loner side is 7 in. and the length of the shorter side is 6 in.

6 0
3 years ago
The average temperature of the atmosphere in the world is approximated as a function of altitude by the relation Tatm=288.15−6.5
Yuri [45]

Answer:

The average temperature of the atmosphere outside the airplane is 206.25\,K.

Step-by-step explanation:

The average temperature of the atmosphere outside an airplane flying at an altitude of 12600 meters is computed by evaluating the linear function:

T (12.6\,km) = 288.15 - 6.5\cdot (12.6\,km)

T (12.6\,km) = 206.25\,K

The average temperature of the atmosphere outside the airplane is 206.25\,K.

3 0
3 years ago
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