Answer:
It's odd.
Explanation:
A function is odd when <span><span>f<span>(−x)</span></span>=−<span>f<span>(x)</span></span></span>
<span><span>f<span>(−x)</span></span>=6<span><span>(−x)</span>3</span>−2<span>(−x)</span></span>
<span>=−6<span>x3</span>+2x</span>
<span>=−<span>(6<span>x3</span>−2x)</span></span>
<span>=−<span>f<span>(x)</span></span></span>
Thus, the function is odd.
If a function is odd, then it is symmetric over the x-axis.
The another way to write (s - 6)(s + 1) is s² - 5s - 6
Step-by-step explanation:
Let us revise how multiply two binomial (a + b)(x + y)
- Multiply the 1st terms
- Multiply the 2nd terms
- Multiply the nears and extremes, where nears are the 2nd term of first bracket and 1st term in the second bracket, the extremes are the 1st term in the first bracket and the 2nd term in the second bracket
- Add the like terms if necessary
∵ The area of the square = (s - 6)(s + 1)
- To find the another way multiply the two brackets
∵ s × s = s²
∵ -6 × 1 = -6
∵ -6 × s = - 6s ⇒ nears
∵ s × 1 = s ⇒ extremes
- The terms - 6s and s are like terms, then add them
∵ - 6s + s = - 5s
∴ (s - 6)(s + 1) = s² - 5s - 6
∴ The area of the square = s² - 5s - 6
The another way to write (s - 6)(s + 1) is s² - 5s - 6
Learn more:
You can learn more about the binomials in brainly.com/question/2334388
#LearnwithBrainly
There are several ways to solve a system of equation; one of these ways is the use of matrix.
<em>Jerry made a mistake at step 2</em>
From the attachment, the step 1 is represented as:
![\mathbf{\frac 12R_1 \left[\begin{array}{cccc}1&1&1&0\\5&3&-2&-4\\3&2&1&1\end{array}\right] }](https://tex.z-dn.net/?f=%5Cmathbf%7B%5Cfrac%2012R_1%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%261%261%260%5C%5C5%263%26-2%26-4%5C%5C3%262%261%261%5Cend%7Barray%7D%5Cright%5D%20%7D)
The equation in step 2 is given as:
This means that:
We subtract the elements of row 2 from the elements of row 1, multiplied by 5
So, we have:
![\mathbf{R_2 = 5\left[\begin{array}{cccc}1&1&1&0\end{array}\right] } - \left[\begin{array}{cccc}5&3&-2&-4\end{array}\right] }](https://tex.z-dn.net/?f=%5Cmathbf%7BR_2%20%3D%205%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%261%261%260%5Cend%7Barray%7D%5Cright%5D%20%7D%20-%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D5%263%26-2%26-4%5Cend%7Barray%7D%5Cright%5D%20%7D)
Expand
![\mathbf{R_2 = \left[\begin{array}{cccc}5&5&5&0\end{array}\right] } - \left[\begin{array}{cccc}5&3&-2&-4\end{array}\right] }](https://tex.z-dn.net/?f=%5Cmathbf%7BR_2%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D5%265%265%260%5Cend%7Barray%7D%5Cright%5D%20%7D%20-%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D5%263%26-2%26-4%5Cend%7Barray%7D%5Cright%5D%20%7D)
Subtract corresponding cells
![\mathbf{R_2 = \left[\begin{array}{cccc}0&2&7&4\end{array}\right] }](https://tex.z-dn.net/?f=%5Cmathbf%7BR_2%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D0%262%267%264%5Cend%7Barray%7D%5Cright%5D%20%7D)
So, the new row 2 elements should be:
![\mathbf{ \left[\begin{array}{cccc}0&2&7&4\end{array}\right] }](https://tex.z-dn.net/?f=%5Cmathbf%7B%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D0%262%267%264%5Cend%7Barray%7D%5Cright%5D%20%7D)
However, the row 2 elements of Jerry's steps are:
![\mathbf{R_2 = \left[\begin{array}{cccc}0&-2&-7&-4\end{array}\right] }](https://tex.z-dn.net/?f=%5Cmathbf%7BR_2%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D0%26-2%26-7%26-4%5Cend%7Barray%7D%5Cright%5D%20%7D)
This means that:
Jerry made a mistake; and the mistake is at step 2
Read more about matrix at:
brainly.com/question/21848291
15 x 3= 45 so therefore 45 is the length hope that help!
Answer:
V= 2 times 4 times 5
Step-by-step explanation:
In order to calculate the volume of a figure u must calculate lwh or length times width times height. In this case length is 5 width is 4 and height is 2. This can be plugged in and becomes 2 times 4 times 5.
