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AnnyKZ [126]
3 years ago
10

Can you help me finish this paper?? I need the answers ASAP!! Plz I will give you 79 points

Mathematics
2 answers:
BlackZzzverrR [31]3 years ago
7 0

ok so you add ok 4. is 23 4 plus 6 plus 8 plus 5 is 23 and you repeat and add on every the first 1. is 16

Yuki888 [10]3 years ago
4 0

Answer:

Step-by-step explanation:

1)22

2)40

3)44

4)62

5)26

6)55

7)29

8)45

9)The picture is not clear

10) 52

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Please help!!!
Alex Ar [27]

Answer:

Check bolded below

Step-by-step explanation:

1)radius = 10 in (given), diameter = 2*radius = 2(10 in) = 20 in

formula for circumference => 2πr => 2π(10)

circumference = 20π in

2)diameter = 12 ft (given), radius = 1/2*diameter = 1/2(12 ft) = 6 ft

formula for circumference => 2πr => 2π(6)

circumference = 12π ft

3)radius = 3 m (given), diameter = 2*radius = 2(3 m) = 6 m

formula for circumference => 2πr => 2π(3)

circumference = 6π m

4)diameter = 18 cm (given), radius = 1/2*diameter = 1/2(18 cm) = 9 cm

formula for circumference => 2πr => 2π(9)

circumference = 18π cm

6 0
3 years ago
Read 2 more answers
Find the components of the vertical force Bold Upper FFequals=left angle 0 comma negative 10 right angle0,−10 in the directions
quester [9]

Solution :

Let $v_0$ be the unit vector in the direction parallel to the plane and let $F_1$ be the component of F in the direction of v_0 and F_2 be the component normal to v_0.

Since, |v_0| = 1,

$(v_0)_x=\cos 60^\circ= \frac{1}{2}$

$(v_0)_y=\sin 60^\circ= \frac{\sqrt 3}{2}$

Therefore, v_0 = \left

From figure,

|F_1|= |F| \cos 30^\circ = 10 \times \frac{\sqrt 3}{2} = 5 \sqrt3

We know that the direction of F_1 is opposite of the direction of v_0, so we have

$F_1 = -5\sqrt3 v_0$

    $=-5\sqrt3 \left$

    $= \left$

The unit vector in the direction normal to the plane, v_1 has components :

$(v_1)_x= \cos 30^\circ = \frac{\sqrt3}{2}$

$(v_1)_y= -\sin 30^\circ =- \frac{1}{2}$

Therefore, $v_1=\left< \frac{\sqrt3}{2}, -\frac{1}{2} \right>$

From figure,

|F_2 | = |F| \sin 30^\circ = 10 \times \frac{1}{2} = 5

∴  F_2 = 5v_1 = 5 \left< \frac{\sqrt3}{2}, - \frac{1}{2} \right>

                   $=\left$

Therefore,

$F_1+F_2 = \left< -\frac{5\sqrt3}{2}, -\frac{15}{2} \right> + \left< \frac{5 \sqrt3}{2}, -\frac{5}{2} \right>$

           $= = F$

3 0
2 years ago
The top of a table is in the shape of a trapezoid. It has a height 1.5 feet and the two parallel bases measure 3 feet and 5 feet
Kobotan [32]

The area of a trapezoid if found using the formula

A = (base1 + base2)/2 x height

Area = (3+5)/2 x 1.5

Area = 8/2 x 1.5

Area = 4 x 1.5

Area = 6 square feet.

3 0
3 years ago
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Which of the following is a solution of y - x &lt; -3?<br><br> (6, 2)<br> (2, 6)<br> (2, -1)
Snowcat [4.5K]
Personally I'd solve this inequality for y first:  y < x-3.

That immediately eliminates (6,2) and (2,6).

Starting from y < x-3 and letting 2 sub for x and -1 sub for y, is the following true or false?

-1 < 2 -3     NO.  -1 < -1 is false.  Was there a fourth answer choice?

5 0
3 years ago
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Please answer for brainlesit
Brums [2.3K]

Answer:

(-3, -2) that is the answer please give me brainiest

Step-by-step explanation:

4 0
3 years ago
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