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3 years ago

-42 < j(7) Solving one step inequalities

Mathematics

1 answer:

kkurt [141]3 years ago

4 0

Step-by-step explanation:

step 1. -42 < 7j

step 2. j > -6 (divide both sides by 7)

step 3. notice that I also put the variable first.

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Simplify (a^-2*b^2/a^2*b^-1) The answer is B

Ad libitum [116K]

Answer:

=b/a^4

Step-by-step explanation:

6 0

3 years ago

Help! I can't figure this out!

Vanyuwa [196]

Answer:

57/6 60/6 22/6 26/6

Step-by-step explanation:

So the answers for the blanks are 57, 60, 22, 26.

Let me know if I am incorrect.

6 0

3 years ago

The length of a rectangle is increasing at a rate of 6 cm/s and its width is increasing at a rate of 5 cm/s. When

atroni [7]

Answer:

The area of the rectangle is increasing at a rate of 84 square centimeters per second.

Step-by-step explanation:

The area for a rectangle is given by the formula:

$A=w\ell$

Where w is the width and l is the length.

We are given that the length of the rectangle is increasing at a rate of 6 cm/s and that the width is increasing at a rate of 5 cm/s. In other words, dl/dt = 6 and dw/dt = 5.

First, differentiate the equation with respect to t, where w and l are both functions of t:

$\displaystyle \frac{dA}{dt}=\frac{d}{dt}\left[w\ell]$

By the Product Rule:

$\displaystyle \frac{dA}{dt}=\frac{dw}{dt}\ell +\frac{d\ell}{dt}w$

Since we know that dl/dt = 6 and that dw/dt = 5:

$\displaystyle \frac{dA}{dt}=5\ell + 6w$

We want to find the rate at which the area is increasing when the length is 12 cm and the width is 4 cm. Substitute:

$\displaystyle \frac{dA}{dt}=5(12)+6(4)=84\text{ cm}^2\text{/s}$

The area of the rectangle is increasing at a rate of 84 square centimeters per second.

8 0

3 years ago

The boeing 747 airplane is 250 feet in length. If a model of this plane is 8 inches long , what scale was used to create this mo

cluponka [151]

Answer: The wingspan is 36 m.

Using a proportion to solve this, we write the scale factor as a ratio first: 19/38, since 19 is the size of the model's length and 38 is the real length. For the second ratio, we have 18 for the size of the model wingspan and x for the real wingspan:

19/38 = 18/x

Cross multiply:

19*x = 38*18

19x = 684

8 0

3 years ago

Please show your work What is the solution of the equation <img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B2x%2B13%7D%20-5%3D

Hatshy [7]

Add the five to each side.
then square it to get rid of the square root
2x+13=(5+x)^2
2x+13=x^2+10x+25
2x=x^2+10x+12
x^2+8x+12=0
(x+6)(x+2)
x+6=0
x+2=0
answers are -2 and -6, however, when pluging -6 in it doesnt work, so it is only -2.

3 0

3 years ago