She had 22 boxes to start
The answer to your question is 29.875
Given that
3 cos 80° cosec 10° + 2 sin 59° sec 31°
⇛3 cos(90°-10°) cosec 10°+2 sin (90°-31°) sec 31°
We know that
sin (90° - A) = cos A
cos (90°-A) = sin A
⇛3 sin 10° cosec 10° + 2 cos 31° sec 31°
⇛3 sin 10° (1/sin 10°) + 2 cos 31° (1/cos 31°)
⇛3 (sin 10°/sin 10°) + 2 (cos 31°/cos 31°)
⇛3 (1) + 2(1)
⇛3+2
⇛5
<u>Answer</u><u>:</u> Therefore, 3cos 80°cosec 10°+2cos 59°sec 31° = 5.
<u>also</u><u> read</u><u> similar</u><u> questions</u><u>:</u> (sin teta + sec teta)^ + (cos teta+ cosec teta )^ = (1 + sec x cosec)^
brainly.com/question/87846?referrer
Answers:
- Enlargement
- The new larger rectangle is 16.8 inches by 8.4 inches
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Explanation:
I'm assuming 7/5 is the scale factor. If so, notice how 7/5 = 1.4 which is larger than 1.
The scale factor being larger than 1 means we have an enlargement.
The image is going to be larger compared to the preimage.
The preimage rectangle is 12 in by 6 in. Multiply each dimension by 1.4 to get 12*1.4 = 16.8 and 6*1.4 = 8.4
The image rectangle is 16.8 inches by 8.4 inches
