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garik1379 [7]
2 years ago
11

If 4 daps = 7 yaps, and 5 yaps = 3 baps, how many daps equal 42 baps? **GIVING OUT BRAINLIEST**

Mathematics
1 answer:
Montano1993 [528]2 years ago
4 0

Answer:

40 daps

Step-by-step explanation:

lets say daps is d, yaps are y and baps are b

4d = 7y, 5y=3b

First convert to y

4/7d = y

Now convert that to b

5(4d/7) = 3b

20d / 7 = 3b

20d / 21 = b

Plug it in:

42(20d/21)

40d

aka 40 daps

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A) Answer: A. 22.5 cm, 30 cm, and 37.5 cm


Setting the unity measurement as x, the three sides will be 3·x, 4·x, and 5·x. The sum of the three sides will be (3 + 4 + 5)·x = 12·x; this corresponds to the perimeter, therefore:

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We can solve for x:

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Hence, the sides will be:

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B) Answer: C. never true


We have:

6 + 8x - 9 = 11x + 14 - 3x


Bring all the terms with x on the left, by subtracting from both sides 11x and -3x, and all the numbers on the right by subtrcting from both sides 6 and -9:

6 + 8x - 9 - 11x - (-3x) - 6 - (-9) = 11x + 14 - 3x - 11x - (-3x) - 6 - (-9)


Cancel out the opposite terms from each side:

8x - 11x + 3x = 14 - 6 + 9


Combine likely terms:

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C) Answer: r \leq \frac{1}{5}


We have:

5r + 4 ≤ 5


Subtract 4 from both sides:

5r + 4 - 4 ≤ 5 - 4


Combine likely terms:

5r ≤ 1


Divide both sides by 5:

\frac{5r}{5} \leq \frac{1}{5}

r \leq \frac{1}{5}


To graph the set of solutions, you need to set:

y₁ = 5x + 4 and

y₂ = +5


Plot these two lines:

y₂ is a horizontal line at a height of 5;

y₁ is a line passing through (0, 4) and (1, 9)


The set of solutions will be the part of the graph in which y₁ lies underneath y₂ (see picture attached), that happens for x \leq \frac{1}{5}.





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Answer:

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Step-by-step explanation:

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