Answer:
In 3 seconds the cup is filled with 
<u>.</u>
Step-by-step explanation:
Given:
2 seconds = 
water
We need to find the percent of the cup that is filled with water after 3 seconds.
Solution:
Now Given:
The cup was filled at a constant rate.
First we will find the volume of water filled in the cup after 1 seconds.
2 seconds = water
1 seconds = Volume of water filled in 1 second.
By Using Unitary method we get;
Volume of water filled in 1 second = 
Now we will find the volume of water filled in the cup after 3 seconds.
1 second = 
of water is filled
3 seconds = volume of water filled in the cup after 3 seconds
Again by using Unitary method we get;
volume of water filled in the cup after 3 seconds = 
Hence In 3 seconds the cup is filled with .
To find the percent of the cup filled with water after 3 seconds we would required the dimensions of the cup which is not available in the question.
I'm assuming that subtraction sign is mean to be an equals sign. If that is true than the answer is 403.75.
Yes it is true! it is true because two different numbers go to the same number, if it was false it would have to be the one number to two different numbers.
Hope that made sense!
Answer:
(x−3)(x−5)
Step-by-step explanation:
Let's factor x2−8x+15
x2−8x+15
The middle number is -8 and the last number is 15.
Factoring means we want something like
(x+_)(x+_)
Which numbers go in the blanks?
We need two numbers that...
Add together to get -8
Multiply together to get 15
Can you think of the two numbers?
Try -3 and -5:
-3+-5 = -8
-3*-5 = 15
Fill in the blanks in
(x+_)(x+_)
with -3 and -5 to get...
(x-3)(x-5)
It's clear that for x not equal to 4 this function is continuous. So the only question is what happens at 4.
<span>A function, f, is continuous at x = 4 if
</span><span>
</span><span>In notation we write respectively
</span>
Now the second of these is easy, because for x > 4, f(x) = cx + 20. Hence limit as x --> 4+ (i.e., from above, from the right) of f(x) is just <span>4c + 20.
</span>
On the other hand, for x < 4, f(x) = x^2 - c^2. Hence
Thus these two limits, the one from above and below are equal if and only if
4c + 20 = 16 - c²<span>
Or in other words, the limit as x --> 4 of f(x) exists if and only if
4c + 20 = 16 - c</span>²
That is to say, if c = -2, f(x) is continuous at x = 4.
Because f is continuous for all over values of x, it now follows that f is continuous for all real nubmers 
