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mojhsa [17]
3 years ago
6

Help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
Oksanka [162]3 years ago
3 0

Answer:

Circumfrence

Step-by-step explanation:

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I suck at this stuff can someone help me out? thank you!
avanturin [10]
A) h=9.9
if that's not correct, i've done these before, i don't know why it wouldn't work?
3 0
4 years ago
The ratio of adults to students on the field trip is 3 to 5. If there are 15 students on the field trip, how many adults are the
Kazeer [188]

Answer:

There are 9 adults

Step-by-step explanation:

3:5 = x:15

3/5 = x/15

3(15) = 5x

5x = 45

x = 9 adults

3:5 = 9:15

4 0
3 years ago
How many fifths are the in 60/100
tankabanditka [31]
In order to calculate that, we need to divide it by 1/5 as follows:
60/100 / 1/5

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So, there are "3" 1/5ths in 60/100

Hope this helps!
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3 years ago
The statement "If 1/2x=5, then x=10 is justified by the
Anton [14]
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6 0
3 years ago
Read 2 more answers
Do one of the​ following, as appropriate.​ (a) Find the critical value z Subscript alpha divided by 2​, ​(b) find the critical v
aliya0001 [1]

Answer:

t=\pm 2.95

Step-by-step explanation:

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The t distribution or Student’s t-distribution is a "probability distribution that is used to estimate population parameters when the sample size is small (n<30) or when the population variance is unknown".

The shape of the t distribution is determined by its degrees of freedom and when the degrees of freedom increase the t distirbution becomes a normal distribution approximately.  

Data given

Confidence =0.99 or 99%

\alpha=1-0.99=0.01 represent the significance level

n =16 represent the sample size

We don't know the population deviation \sigma

Solution for the problem

For this case since we don't know the population deviation and our sample size is <30 we can't use the normal distribution. We neeed to use on this case the t distribution, first we need to calculate the degrees of freedom given by:

df=n-1=16-1=15

We know that \alpha=0.01 so then \alpha/2=0.005 and we can find on the t distribution with 15 degrees of freedom a value that accumulates 0.005 of the area on the left tail. We can use the following excel code to find it:

"=T.INV(0.005;15)" and we got t_{\alpha/2}=-2.95 on this case since the distribution is symmetric we know that the other critical value is t_{\alpha/2}=2.95

8 0
4 years ago
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