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mojhsa [17]
3 years ago
6

Help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
Oksanka [162]3 years ago
3 0

Answer:

Circumfrence

Step-by-step explanation:

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Find the slope of the line that contains these points.(5,1) (-3,1)
shtirl [24]
Slope equals change in y divided by change in x.

m=(y2-y1)/(x2-x1)

m=(1-1)/(5--3)

m=0/8

m=0

The slope is zero.

So this is a horizontal line of the form y=1
3 0
3 years ago
What is 4 times 4 and 5555 times 8999989
Ket [755]

Answer:

4 *4 = 16

16 * 5555 = 88880

88880 * 8999989 = 799919022320

Brainliest :D

Step-by-step explanation:

8 0
2 years ago
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What is Y=2(3x+6)(5x-4)
Sliva [168]

Answer:

y=30x^2+36x+48 OR f(x)=30x^2+36x+48

This is an exponential function/exponential graph. Hope I helped!

Step-by-step explanation:

Given: y=2(3x+6)(5x-4)

Use the distributive property!: y=(6x+12)(5x-4)

Use the distributive property!: y=(5x(6x+12)-4(6x+12))

Use the distributive property!: y=(30x^2+60x)-(24x+48)

Remove parenthesis: y=30x^2+60x-24x+48y=30x^2+36x+48 OR f(x)=30x^2+36x+48

This is an exponential function/exponential graph. Hope I helped!

8 0
3 years ago
Use substitution to solve this problem<br>a=5, b=2<br>5a - b = ‽<br>​
Rom4ik [11]
Plug the numbers into the equation

5(5) - 2 = ?

25 -2 = 23

23
3 0
3 years ago
Find the 12th term of the geometric sequence 5, -25, 125, ...5,−25,125,...
katovenus [111]

Answer:

  • a_{12}=-244140625

Step-by-step explanation:

Considering the geometric sequence

5,-25,\:125,\:...

a_1=5

As the common ratio 'r' between consecutive terms is constant.

\mathrm{Compute\:the\:ratios\:of\:all\:the\:adjacent\:terms}:\quad \:r=\frac{a_{n+1}}{a_n}

r=\frac{-25}{5}=-5

r=\frac{125}{-25}=-5

The general term of a geometric sequence is given by the formula:  

a_n=a_1\cdot \:r^{n-1}

where a_1 is the initial term and r the common ratio.

Putting n = 12 , r = -5 and a_1=5 in the general term of a geometric sequence to determine the 12th term of the sequence.

a_n=a_1\cdot \:r^{n-1}

a_n=5\left(-5\right)^{n-1}

a_{12}=5\left(-5\right)^{12-1}

      =5\left(-5^{11}\right)

\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a

       =-5\cdot \:5^{11}

\mathrm{Apply\:exponent\:rule}:\quad \:a^b\cdot \:a^c=a^{b+c}

        =-5^{1+11}     ∵ 5\cdot \:5^{11}=\:5^{1+11}

        =-244140625

Therefore,

  • a_{12}=-244140625
6 0
3 years ago
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