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3 years ago

Help me Pls its due soon and i have no clue how to do this

Mathematics

1 answer:

Alekssandra [29.7K]3 years ago

6 0

Question 10

Draw a 30-60-90 triangle template. Refer to the diagram below.

We have 1 as the short leg, 2 as the hypotenuse and sqrt(3) as the long leg.

Place the angle theta as the reference angle such that it's opposite the sqrt(3) side.

That allows tan(theta) = sqrt(3)/1 = opposite/adjacent

In other words, tan(60) = sqrt(3)/1

So theta = 60 is one solution. We add on 180 to get the other solution. So the other solution is 60+180 = 240

So tan(60) = tan(240) = sqrt(3)

<h3>Answers: 60 and 240</h3>

======================================================

Question 11a

sin(theta) = -0.8

theta = arcsin(-0.8) or theta = 180-arcsin(-0.8)

theta = -53.1301 or theta = 180 - (-53.1301)

theta = -53.1301 or theta = 233.1301

Add 360 to the first angle to find a coterminal angle counterpart.

-53.1301 + 360 = 306.8699

So the two approximate solutions are

theta = 306.8699 or theta = 233.1301

and those round to 306.9 and 233.1 respectively.

<h3>Answers: 233.1 and 306.9 </h3>

======================================================

Question 11b

cot(theta) = 1.8

tan(theta) = 1/(1.8)

theta = arctan( 1/(1.8) ) or theta = 180+arctan( 1/(1.8) )

theta = 29.0546 or theta = 180+29.0546

theta = 29.0546 or theta = 209.0546

theta = 29.1 or theta = 209.1

<h3>Answers: 29.1 and 209.1</h3>

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