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3 years ago

Ok fr I need to stop ima get banned lol last one yallll

Mathematics

2 answers:

ValentinkaMS [17]3 years ago

5 0

Umm lol but sweet thanks

Stells [14]3 years ago

3 0

Answer:

that looks nice.........

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How many zeros are in one million?

Julli [10]

Answer:

six

Step-by-step explanation:

1,000,000

5 0

3 years ago

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A tortoise is walking in the desert. It walks at a speed of 2 meters per minute for 2.56 meters. For how many minutes does it wa

zaharov [31]

distance = rate * time

2.56 meters = 2meter/min * t

divide by 2 on each side

2.56/2 =t

1.28 minutes =t

8 0

3 years ago

Please answer correctly !!!!!!!!! Will<br> Mark brainliest !!!!!!!!!!!!!

il63 [147K]

Answer:

$x=-\frac{-20+\sqrt{-20w+3600}}{10},\:x=-\frac{-20-\sqrt{-20w+3600}}{10}$

Step-by-step explanation:

$w=-5\left(x-8\right)\left(x+4\right)\\\mathrm{Expand\:}-5\left(x-8\right)\left(x+4\right):\quad -5x^2+20x+160\\w=-5x^2+20x+160\\Switch\:sides\\-5x^2+20x+160=w\\\mathrm{Subtract\:}w\mathrm{\:from\:both\:sides}\\-5x^2+20x+160-w=w-w\\Simplify\\-5x^2+20x+160-w=0\\Solve\:with\:the\:quadratic\:formula\\\mathrm{Quadratic\:Equation\:Formula:}\\\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:}\quad a=-5,\:b=20,\:c=160-w:\quad x_{1,\:2}=\frac{-20\pm \sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}\\x=\frac{-20+\sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}:\quad -\frac{-20+\sqrt{-20w+3600}}{10}\\x=\frac{-20-\sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}:\quad -\frac{-20-\sqrt{-20w+3600}}{10}\\The\:solutions\:to\:the\:quadratic\:equation\:are\\x=-\frac{-20+\sqrt{-20w+3600}}{10},\:x=-\frac{-20-\sqrt{-20w+3600}}{10}$

6 0

3 years ago

A solid oblique pyramid has an equilateral triangle as a base with an edge length of 4 cm and an area of 12 cm2. What is the vol

Pavel [41]

Solution:

Let me define pyramid first.A pyramid is a Polyhedron , whose base can be any polygon and it's faces are triangular which meet at a point called vertex.

Volume of Pyramid = $\frac{1}{2}\times{\text{Area of Base}\times{\text{Height}$

Side of base which is an equilateral triangle= 4 cm

Area of whole pyramid = 12 square cm

Area of Equilateral triangle having side 4 cm= $\frac{\sqrt3}{4}\times(Side)^2=\frac{\sqrt3}{4}\times(4)^2=4 \sqrt3$ cm²

So, Area of three triangle which are faces of pyramid = (12 - 4 √3)cm²

Area of triangle = $\frac{1}{2} \times (Base)\times(Height)$

12 - 4 √3= $\frac{1}{2} \times (4)\times(Height)$

Height = $\frac{12-4\sqrt3}{2}$

Height=(6-2√3) cm

Volume of pyramid = Area of Equilateral triangle which is it's Base × Height of Pyramid

=4√3 × (6-2√3) cm³

=(24 √3 -24)

= 24 (1.732-1)

=24 × 0.732

=17.568 cm³

8 0

3 years ago

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8 3/8 = r- 2 1/3 how do i solve this equation by finding out what r is.

BaLLatris [955]

First, convert your mixed numbers into improper fractions, so 8+3/8=69/8 and 2+1/3=7/3. Now you have 69/8=r-(7/3). Now, add 7/3 to both sides, so (69/8)+(7/3)=r. Now, just add your fractions, so (69/8)+(7/3)=207/24+56/24=(207+56)/24=263/24. If you need to, this can be converted back into the mixed number 10+23/24.

7 0

3 years ago