Answer:
13.09 pounds, 13,10 pounds if you have to round, which is not clear (result is 13.095).
Answer:
really hard
Step-by-step explanation:
ask sheldon
It's unlikely that it the dimensions are either 14 and 1 in front of the x or 6 and 1 for the 6, but this is math, so you never know. I would try 7 and 2 and 3 and 2 and see what comes of it.
(7x 2)(2x 3 ) That looks promising. We'll put the 3 with the 2x. That leaves us with the signs. We need 17 to be minus
(7x 2)(2x - 3) that gives you - 21 x So the 2 with the seven has to be plus.
(7x + 2)(2x - 3) should be the the factored answer.
7x + 2 = 0 has no meaning. Measurements cannot be minus.
2x - 3 = 0
2x = 3
x = 3/2
If there are choices, please list them. That's as far as is possible.
(n^3-8)(n^3+1)
It requires the same thought process of simplifying x^2-7x-8.
We know that the angles of a triangle sum to 180°. For ΔABC, this means we have:
(4x-10)+(5x+10)+(7x+20)=180
Combining like terms,
16x+20=180
Subtracting 20 from both sides:
16x=160
Dividing both sides by 16:
x=10
This means ∠A=4*10-10=40-10=30°; ∠B=5*10+10=50+10=60°; and ∠C=7*10+20=70+20=90.
For ΔA'B'C', we have
(2x+10)+(8x-20)+(10x-10)=180
Combining like terms,
20x-20=180
Adding 20 to both sides:
20x=200
Dividing both sides by 20:
x=10
This gives us ∠A'=2*10+10=20+10=30°; ∠B'=8*10-20=80-20=60°; and ∠C'=10*10-10=100-10=90°.
Since the angle are all congruent, ΔABC~ΔA'B'C' by AAA.
