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4 years ago

What value for x makes the equation true?

Mathematics

1 answer:

fgiga [73]4 years ago

8 0

Since we already have 3^7 you should know that 3 times 3 is 9. Here is how I would simplify it.

3^7 times 3^4 times 3^3

You should add all the exponents and get

3^14

27 is basically 3 times 3 times 3 which is why I chose to put 27 that way

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Help help i need help anyone ?

REY [17]

-9-6i/-3-2i
Factor -3 out of expression
-3(3+2i)/-3-2i
Then extract the negative sign out of the expression
-3(3+2i)/-(3+2i)
Reduce the fraction with -(3+2i)
-3/-1
-3*-1=3
Hope this helps

3 0

3 years ago

URGENT NEED ANSWERS •_•

Anna11 [10]

9. 130 = x + 137
answer x = -7

10. 9x-3 = 4 + 8x
9x = 7 + 8x
answer x = 7

4 0

3 years ago

#1 Factors Which of these numbers is a factor of 49? a. 9 b. 7 C. 6 d. 5

Vesna [10]

Answer = b. 7

THANK YOU FOR LISTENING TO MY TED TALK

8 0

3 years ago

PLEASE HELP I WILL MARK YOU BRAINLIEST Marjorie brought in 3 ½ pounds of candy and Layla brought in 2 ½ pounds of candy to contr

aniked [119]

Answer:

Step-by-step explanation:

3.5+2.5=6

6/0.25=6x4

8 0

3 years ago

Consider Functions F and G

Zanzabum

Answer:

Step-by-step explanation:

We are given two functions:

$\displaystyle f(x)=\frac{x-16}{x^2+6x-40}\text{ and } g(x)=\frac{1}{x+10}$

And we want to find:

$f(x)+g(x)$

Thus:

$\displaystyle =\frac{x-16}{x^2+6x-40}+\frac{1}{x+10}$

We can factor the denominator of the first term:

$\displaystyle =\frac{x-16}{(x+10)(x-4)}+\frac{1}{x+10}$

In order to add the two terms, we must have a common denominator. To achieve this, we can multiply to second term by (x - 4). Therefore:

$\displaystyle =\frac{x-16}{(x+10)(x-4)}+\frac{1}{x+10}\Big(\frac{x-4}{x-4}\Big)$

Multiply:

$\displaystyle =\frac{x-16}{(x+10)(x-4)}+\frac{x-4}{(x+10)(x-4)}$

Combine:

$\displaystyle =\frac{(x-16)+(x-4)}{(x+10)(x-4)}$

Simplify:

$\displaystyle =\frac{2x-20}{(x+10)(x-4)}$

We can expand the denominator:

$\displaystyle =\frac{2x-20}{x^2+6x-40}$

Therefore, our answer is A.

6 0

3 years ago

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