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Lelu [443]
3 years ago
8

Can someone please help me with these 4 questions?

Mathematics
1 answer:
Harman [31]3 years ago
7 0
16. Is 77=x
Sqrt 2x+15=13
169=2x+15
154=2x
77=x
You might be interested in
consider the line shown on the graph. enter the equation of the line in the form y=mx where m is the slope.
Amanda [17]

Answer:

y= 3x

Step-by-step explanation:

6 0
3 years ago
Suppose that the mean water hardness of lakes in Kansas is 425 mg/L and these values tend to follow a normal distribution. A lim
tino4ka555 [31]

Answer:

The mean water hardness of lakes in Kansas is 425 mg/L or greater.

Step-by-step explanation:

We are given the following data set:

346, 496, 352, 378, 315, 420, 485, 446, 479, 422, 494, 289, 436, 516, 615, 491, 360, 385, 500, 558, 381, 303, 434, 562, 496

Formula:

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}  

where x_i are data points, \bar{x} is the mean and n is the number of observations.  

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{10959}{25} =438.36

Sum of squares of differences = 175413.76

S.D = \sqrt{\dfrac{175413.76}{24}} = 85.49

Population mean, μ = 425 mg/L

Sample mean, \bar{x} = 438.36

Sample size, n = 25

Alpha, α = 0.05

Sample standard deviation, s = 85.49

First, we design the null and the alternate hypothesis

H_{0}: \mu \geq 425\text{ mg per Litre}\\H_A: \mu < 425\text{ mg per Litre}

We use one-tailed t test to perform this hypothesis.

Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }

Putting all the values, we have

t_{stat} = \displaystyle\frac{438.36 - 425}{\frac{85.49}{\sqrt{25}} } = 0.7813

Now, t_{critical} \text{ at 0.05 level of significance, 24 degree of freedom } = -1.7108

Since,                        

The calculated t-statistic is greater than the critical value, we fail to reject the null hypothesis and accept it.

Thus, the mean water hardness of lakes in Kansas is 425 mg/L or greater.

6 0
3 years ago
The width of a rectangle is 7 inches less than its length. The area of the rectangle is 120 square inches. Solve for the dimensi
pav-90 [236]

Answer:

Length is 15 inches

Width is 8 inches

Step-by-step explanation:

A = L*W

the Width = L-7

120 = L (L-7)

120 = L^2-7L

subtract 120 from each side

0 = L^2 - 7L - 120

(L-15) (L +8 )

so L = 15  inches

and W = 15-7 = 8 inches

check your answer: does 15*8 = 120? yes!

6 0
3 years ago
(-9, -5) and (-1, -9)<br> find the midpoint
irga5000 [103]

Answer:

(-5,-7)

Step-by-step explanation:

6 0
3 years ago
Simplify the expression (x+5)2
Lina20 [59]
2x+10, multiply to two each term x and 5
4 0
3 years ago
Read 2 more answers
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