All categories

2 years ago

Helppp meeeeeeeeeeeeeeeeeee

Mathematics

2 answers:

dsp732 years ago

7 0

Answer:

-2/-3

Step-by-step explanation:

Just do it

Veronika [31]2 years ago

5 0

Answer:

First

Step-by-step explanation:

You might be interested in

3x+6y=24 turned into a graphing equation

Talja [164]

Answer:

Step-by-step explanation:

3x + 6y = 24

6y = -3x + 24

y = -3/6x + 24/6

y = -1/2x + 4 <=====

5 0

3 years ago

Read 2 more answers

You start a lawn care company with four friends. You agree to split the profits equally. The tools you need to buy cost $525. Ho

elena55 [62]

Because you're starting the company with 4 friends, there are 5 people in total. Therefore, if you do (400 × 5) + 525, you get the answer. 400 × 5 = 2000, and 2000 + 525 = $2525. I hope this helps! Let me know if you need me to explain anything :)

6 0

3 years ago

Please help this is due today please i really need help it’s due in 4 hours!!!

Anarel [89]

Answer:

y=36 and X=44

Step-by-step explanation:

7 0

2 years ago

5x-2y=30 complete the missing solution to the equation

astra-53 [7]

Answer:

I would have to go with x = 8 and y = 5, meaning the solution is (8, 5).

Step-by-step explanation:

$5x - 2y = 30$

$5(8) - 2(5) = 30$

$40 - 10 = 30$

$30 = 30$

4 0

2 years ago

Read 2 more answers

(1 point) consider the function f(t)=⎧⎩⎨⎪⎪⎪⎪0,−5,−6,6,t<00≤t<11≤t<7t≥7;f(t)={0,t<0−5,0≤t<1−6,1≤t<76,t≥7; 1. wr

sergij07 [2.7K]

$f(t)=\begin{cases}0&\text{for }t$

Recall that

$u(t)=\begin{cases}0&\text{for }t$

Take it one piece at a time. For $t\ge0$ , we can scale $u(t)$ by -5:

$-5u(t)=\begin{cases}0&\text{for }t$

If we shift the argument by 1 and scale by -5, we have

$-5u(t-1)=\begin{cases}0&\text{for }t$

so if we subtract this from $-5u(t)$ , we'll end up with

$-5u(t)+5u(t-1)=\begin{cases}0&\text{for }t$

For the next piece, we can add another scaled and shifted step like

$-6u(t-1)+6u(t-7)=\begin{cases}0&\text{for }t$

so that

$-5u(t)+5u(t-1)-6u(t-1)+6u(t-7)=\begin{cases}0&\text{for }t$

For the last piece, we add one more term:

$6u(t-7)=\begin{cases}0&\text{for }t$

and so putting everything together, we get $f(t)$ :

$f(t)\equiv-5u(t)+5u(t-1)-6u(t-1)+6u(t-7)+6u(t-7)$
$f(t)\equiv-5u(t)-u(t-1)+12u(t-7)$

5 0

3 years ago