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Westkost [7]
3 years ago
12

Solve for x, 1. -2x+4=18 2. x/3 - 1=5

Mathematics
2 answers:
rodikova [14]3 years ago
5 0
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

x-15/4-(1/18)=0

liberstina [14]3 years ago
3 0

1. x = -7

2. x = 18

I HOPE IT HELPS! And can I get brainiest?

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ehidna [41]
The answer would be c.0.89
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3 years ago
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Find the next three terms in the geometric sequence -36, 6, -1, 1/6
Salsk061 [2.6K]

Answer:

in fraction form: -1/36, 1/216, -1/1296

in decimal form: -.03, .005, -.0008

Step-by-step explanation:

Each term is the previous term divided by -6:

-36 ÷ -6= 6

6 ÷ -6= -1

and so on...

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3 years ago
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3. In New York, the Mega Ball jackpot lottery asks you to pick 5 numbers (integers) from 1 to 59 (the "upper
svlad2 [7]

Answer:

P = 0.000000028514

Step-by-step explanation:

First we are going to calculate the probability of correctly choosing exactly 4 of the winning numbers.

Remember that the probability of an event can be calculated thus:

P = \frac{favourable - cases}{total -cases}

The favorable cases resulting from choosing 4 numbers of the set of 5 winning numbers from the upper section.

The favorable cases can be calculated with a combinatorial thus:

5C4 = \frac{5!}{(5-4)!4!} =5

and the total cases are:

59C5 = \frac{59!}{(59-5)!5!} = 5006386

Then the probability is:

P = \frac{5}{5006386} = 0.000000998

and the probability of correctly choosing  the Mega Ball number is:

P = \frac{1}{35} = 0.0285714

And how both events are independent the probability of correctly choosing exactly 4 of the winning numbers and the Mega Ball number is:

P = (0.000000998)(0.0285714)

P = 0.000000028514

8 0
3 years ago
In 2009, Pablo Sandoval had 633 plate appearances, with 189 hits and 25 home runs. He was paid $401,750. If he played 153 games,
svet-max [94.6K]

Answer:

\$2,625,82\ per\ game\ played

Step-by-step explanation:

we know that

To find out how much he was paid for each game he played, divide the total paid by the number of games played

so

\frac{401,750}{153}=\$ 2,625,82\ per\ game\ played

6 0
4 years ago
Please help quickly 15 POINTS
DedPeter [7]
37.88888888 and it just keep repearing so there is no right answer dont foeget to mark me as the best answer
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3 years ago
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