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3 years ago

What is the absolute value of a number

Mathematics

1 answer:

Afina-wow [57]3 years ago

8 0

Answer:

Value of a number regardless of sign or symbol

|5| = 5

|-5| = 5

-|5| = -5

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Ivanshal [37]

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3 years ago

Solve the following equation using the distributive property. 4(x-3)=5

bazaltina [42]

Answer:

Step-by-step explanation:

The distributive property states that $A(B + C) = AB + AC$

So:

$4(x-3)=5\\\\4x-12=5\\\\4x=17\\\\x=\frac{17}{4}=4.25$

Hope that makes sense!

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3 years ago

Read 2 more answers

Mara finished 1/5 and 3/8 . what fraction she complete

lesya692 [45]

FIrst you need common denominators for both fraction so the common denominator would be 40 so both fractions look like this
1/40 and 3/40 now you and and you get 4/40 but now you can simplify that down by divinig by 4 and your fraction will be 1/10

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4 years ago

Y+1 y+8 y+2 y+7

kipiarov [429]

$\dfrac{y+1}{y+2}+\dfrac{y+8}{y+9}=\dfrac{y+2}{y+3}+\dfrac{y+7}{y+8}$

Write all fractions in terms of a common denominator:

$\dfrac{y+1}{y+2}=\dfrac{(y+1)(y+9)(y+3)(y+8)}{(y+2)(y+9)(y+3)(y+8)}$

$\dfrac{y+8}{y+9}=\dfrac{(y+8)^2(y+2)(y+3)}{(y+2)(y+9)(y+3)(y+8)}$

$\dfrac{y+2}{y+3}=\dfrac{(y+2)^2(y+9)(y+8)}{(y+2)(y+9)(y+3)(y+8)}$

$\dfrac{y+7}{y+8}=\dfrac{(y+7)(y+2)(y+9)(y+3)}{(y+2)(y+9)(y+3)(y+8)}$

Then move all fractions to one side and simplify the numerator:

$\dfrac{(y+1)(y+9)(y+3)(y+8)+(y+8)^2(y+2)(y+3)-(y+2)^2(y+9)(y+8)-(y+7)(y+2)(y+9)(y+3)}{(y+2)(y+9)(y+3)(y+8)}=0$

The numerator dictates when the fraction reduces to 0. The denominator can never be 0, so we know that <em>y</em> cannot take any of the values -2, -9, -3, nor -8.

So the equation reduces to

$(y+1)(y+9)(y+3)(y+8)+(y+8)^2(y+2)(y+3)-(y+2)^2(y+9)(y+8)-(y+7)(y+2)(y+9)(y+3)=0$