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3 years ago

8

Andre says that 3 divided by 2/3 equals 4 and 1/3 because there are four groups of 2/3 and 1/3 left. Do you agree with Andre? Ex

plain your reasoning.

1 answer:

podryga [215]3 years ago

5 0

Answer:

No I do not agree with Andre

Step-by-step explanation:

Andre says that 3 divided by 2/3

Solving for 3 ÷ 2/3

3 ÷ 2/3

= 3 × 3/2

= 9/2

= 4 1/2

Therefore, 3 divided by 2/3 is 4 1/2

Andre's reasoning is wrong.

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4 years ago

Graph the line that represents this equation:y=-2/3x +1

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Answer:

(attached below)

Step-by-step explanation:

I have attached what your graph should look like with 1 being the y intercept and -2/3 being your slope

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3 years ago

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3 years ago

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Part A: Plot the points A(-8,7) and B(6,-9). Mark the halfway point on AB and label it point M. What are the coordinates of M? P

vredina [299]

Answer:

a. $M(x,y) = (-1,-1)$

b. $D(-4,-9)$

Step-by-step explanation:

Given

A(-8,7) and B(6,-9).

Solving (a):

Determine the Midpoint M;

This is calculated as follows;

$M(x,y) = (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

Where

$(x_1,y_1) = (-8,7)$

$(x_2,y_2) = (6,-9)$

Substitute these values in the formula

$M(x,y) = (\frac{-8+6}{2},\frac{7-9}{2})$

$M(x,y) = (\frac{-2}{2},\frac{-2}{2})$

$M(x,y) = (-1,-1)$

<em>Hence; the midpoint is (-1,-1)</em>

Solving (a):

Here, we have

C = (2,7)

M; Midpoint = (-1,-1)

Required: Determine D

This is calculated as follows;

$M(x,y) = (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

Where

$(x_1,y_1) = (2,7)$

$(x,y) = (-1,-1)$

Substitute these values in the formula

$(-1,-1) = (\frac{2+x_2}{2},\frac{7+y_2}{2})$

Solving for x2

$-1 = \frac{2 + x_2}{2}$

Multiply both sides by 2

$-2 = 2 + x_2$

Subtract 2 from both sides

$x_2 = -2 - 2$

$x_2 = -4$

Solving for y2

$-1 = \frac{7 + y_2}{2}$

Multiply both sides by 2

$-2 = 7 + y_2$

Subtract 7 from both sides

$y_2 = -2 - 7$

$y_2 = -9$

Hence, the coordinates of D is

$D(-4,-9)$

7 0

4 years ago

Write the standard form equation of the line through the given points. through (0.-4) and (-3,-2)

Alexxx [7]

Answer:

The standard form of equation of the line through the given points. through (0.-4) and (-3,-2) is $\frac{2}{3}x+y=-4$

Step-by-step explanation:

The standard form of equation is $Ax+By=C$

Finding slope

Using the given points (0,-4) and (-3,-2) we can find slope using formula: $Slope=\frac{y_2-y_1}{x_2-x_1}$

$Slope=\frac{-2-(-4)}{-3-(0)}\\Slope=\frac{-2+4}{-3} \\Slope=-\frac{2}{3}$

Finding y-intercept

Using point (0,4) and Slope=-2/3 we can find y-intercept

$y=mx+b\\-4=-\frac{2}{3}(0)+b\\-4=0+b\\b=-4$

The slope intercept form of the line through the given points. through (0.-4) and (-3,-2) having slope =-2/3 and b=-4 will be:

$y=mx+b\\y=-\frac{2}{3}x-4$

Now, standard form of equation will be: $\frac{2}{3}x+y=-4$

So, The standard form of equation of the line through the given points. through (0.-4) and (-3,-2) is $\frac{2}{3}x+y=-4$

4 0

3 years ago