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hoa [83]
3 years ago
9

Capacity of coffee mug

Mathematics
1 answer:
Katarina [22]3 years ago
3 0
<span>the medium coffee cup has  a capacity 12 fl-oz volume. the large cup contains 16 fluid ounces capacity in volume. and the extra large, or jumbo cup, is 20 fl oz large. the standard mug size holds 12 fluid ounces of a liquid.</span>
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What is the value of f(g(1)
ladessa [460]

Composite functions is a way of substituting one function into another. The value of the composite function f(g(1)) is 1

<h3>Composite functions</h3>

Composite functions is a way of substituting one function into another.


Given the function expressed as:

y = 3√x + 1

g(1) from the mapping is 0

Substitute g(1) = 0 into the given function to have:

f(g(1)) =  3√0 .+ 1

f(g(1)) =0 + 1
f(g(1))  = 1

Hence the value of the composite function f(g(1)) is 1

Learn more on composite function here: brainly.com/question/10687170

#SPJ1

7 0
2 years ago
What is the MINIMUM of the data set: 35, 20, 30,25, 20?"
Romashka [77]

Answer:

B) 20

<u>The minimum of a data set is the </u><u>smallest</u><u> term of that set.</u>

We arrange the terms in ascending order

→ 20,20,25,30,35

So, the minimum is 20

<u>--------------------------------</u>

<u>hope it helps...</u>

<u>have a great day!!</u>

3 0
2 years ago
(HELP PLEASE) graph and shade the solution of the system of enequalities below (HELP PLEASE!)
MAVERICK [17]
A b and 3 is the correct answer
8 0
3 years ago
Solve for the missing length and the other two angles in the triangle below
Klio2033 [76]

Answer:

AC = 3.72 units

Angles:

A = 132.6°

C = 27.4°

Step-by-step explanation:

AC² = 5² + 8² - 2(5)(8)cos(20)

AC² = 13.82459034

AC = 3.718143399

3.718143399/sin20 = 8/sinA

sinA = 0.7358944647

A = 180 - 47.38285134

A = 132.6171487

3.718143399/sin20 = 5/sinC

sinC = 0.4599340405

C = 27.38285134

5 0
3 years ago
A random sample of 144 recent donations at a certain blood bank reveals that 81 were type A blood. Does this suggest that the ac
Reptile [31]

Answer:

Null hypothesis:p=0.4  

Alternative hypothesis:p \neq 0.4

z=\frac{0.5625 -0.4}{\sqrt{\frac{0.4(1-0.4)}{144}}}=3.98  

p_v =2*P(z>3.98)=0.0000689  

Since the p value is very low compared to the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true percent of people with type A of blood is significantly different from 0.4 or 40%

Step-by-step explanation:

Information given

n=144 represent the random sample taken

X=81 represent the number of people with type A blood

\hat p=\frac{81}{144}=0.5625 estimated proportion of  people with type A blood

p_o=0.4 is the value that we want to verify

\alpha=0.01 represent the significance level

z would represent the statistic

p_v{/tex} represent the p value Hypothesis to testWe want to test if the percentage of the population having type A blood is different from 40%.:  Null hypothesis:[tex]p=0.4  

Alternative hypothesis:p \neq 0.4  

the statistic is given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing the info given we got:

z=\frac{0.5625 -0.4}{\sqrt{\frac{0.4(1-0.4)}{144}}}=3.98  

Now we can calculate the p value with this probability taking in count the alternative hypothesis:

p_v =2*P(z>3.98)=0.0000689  

Since the p value is very low compared to the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true percent of people with type A of blood is significantly different from 0.4 or 40%

3 0
3 years ago
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