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Sav [38]
3 years ago
10

Write a decimal where the value of a digit is 1/10 as much as a digit in another place

Mathematics
1 answer:
Igoryamba3 years ago
4 0
Some examples are:
1.22 
5.51
6.64
-4.11
Basically all you need to do is have 2 of the same digit next to each other.
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Select the correct answer.
tigry1 [53]

Answer:

We can be 95% certain that the sample mean will fall within $44.87 and $46.93

Step-by-step explanation:

Empirical Rule:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

Central Limit Theorem:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Population:

Mean $45.90, standard deviation $10.31.

Sample:

By the Central limit theorem, mean $45.90, standard deviation s = \frac{10.31}{\sqrt{400}} = \frac{10.31}{20} = 0.5155

Which interval can the branch manager be 95% certain that the sample mean will fall within?

By the Empirical Rule, within 2 standard deviations of the mean. So

45.90 - 2*0.5155 = $44.87

45.90 + 2*0.5155 = $46.93

We can be 95% certain that the sample mean will fall within $44.87 and $46.93

6 0
2 years ago
Read 2 more answers
The symphonic choir and the jazz choir are recording songs for an album. The album can be no more than 72 minutes long. The jazz
zimovet [89]

Answer:

The symphonic choir can record a maximum of 14 songs.

Step-by-step explanation:

We know that the album cannot be more than 72 minutes long, and the jazz choir records a total of 7 (3min) = 21  song minutes.

If we call c the number of songs the symphonic choir records , and each song is 3.5 minute long, then the song minutes for the symphonic choir are 3.5c; therefore, we have the inequality

3.5c+21\leq 72<em> (this says the song minutes for jazz choir plus song minutes for symphonic choice cannot exceed 72 minutes )</em>

We solve this inequality by subtracting 21 from both sides and then dividing by 3.5:

3.5c\leq 51

$c\leq \frac{51}{3.5} $

c\leq 14.47

The maximum integer value c can take is 14; therefore, the maximum number of songs the symphonic choir can record is 14 songs.

3 0
3 years ago
What is the product of (2x-7) and (3x + 3)?
eduard
<h3>✒️EVALUATION </h3>

==================================

\large\sf\underline{Problem:}

What is the product of (2x-7) and (3x + 3)?

  • A. 6x2 + 15x-21
  • B. 6x2 - 15x - 21
  • C. 6x2 + 15x + 21
  • D. 6x2 - 15x + 21

==================================

\large\sf\underline{Answer:}

\qquad \qquad \huge \rm Letter\:B.

*Please read and understand my solution. Don't just rely on my direct answer*

==================================

\large\sf\underline{Solution:}

Here we have the given choices:

  • A. 6x2 + 15x-21
  • B. 6x2 - 15x - 21
  • C. 6x2 + 15x + 21
  • D. 6x2 - 15x + 21

Solve this equation using the distributive property,where you multiply each term to get the number.

\begin{gathered} \rm2x - 7 = \boxed{ 6} \: \bigg| \small\boxed{\: 6 {x}^{2} } \\ \rm (7)(3) = \boxed{21} \bigg | \boxed{\: 21 x} \\ \\ \qquad \rm6x^{2}+(6x- 21x)-21 \\ \qquad \boxed{ \rm6 {x}^{2} + 15x - 21}\end{gathered}

Therefore, the correct option is letter B.

==================================

ヾ(^-^)ノ

3 0
2 years ago
Largest exponent in a polynomial is called it’s ___.
Nadusha1986 [10]

Largest exponent in a polynomial is called it’s Degree

4 0
3 years ago
Read 2 more answers
A restaurant serves custom-made omelets, where guests select meat, cheese, and vegetables to be added to their omelet. There are
kondor19780726 [428]

Answer: The number of different combinations of 2 vegetables are possible = 15 .

Step-by-step explanation:

In Mathematics , the number of combinations of selecting r values out of n values = ^nC_r=\dfrac{n!}{r!(n-r)!}

Given : Number of available vegetables = 6

Then, the number of different combinations of 2 vegetables are possible will be :

^6C_2=\dfrac{6!}{2!(6-2)!}=\dfrac{6\times5\times4!}{2\times4!}=15

Hence , the number of different combinations of 2 vegetables are possible = 15 .

5 0
3 years ago
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