Question

Please help 20 pnts!!

Answer 1

Answer:

$m^{\frac{1}{2} }$ . $n^{\frac{1}{2} }$

Step-by-step explanation:

Using the rules of exponents/ radicals

$\sqrt{a}$ × $\sqrt{b}$ ⇔ $\sqrt{ab}$

$\sqrt{a}$ = $a^{\frac{1}{2} }$

Given

$\sqrt{mn}$

= $\sqrt{m}$ × $\sqrt{n}$

= $m^{\frac{1}{2} }$ . $n^{\frac{1}{2} }$

Answer 2

Answer:

${(mn)}^{ \frac{1}{2} } \\ {m}^{ \frac{1}{2} } {n}^{ \frac{1}{2} }$