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icang [17]
3 years ago
8

How many ones can you take from seventeen

Mathematics
1 answer:
nalin [4]3 years ago
3 0

Answer:

Step-by-step explanation:

Well, if you do 1 times any number then it will still be that number.

so the number of ones that you can take from 17 is well, 17.

Hope this helps!

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Jennifer needs to make an average of at least $350 per week. If she makes $385, $326, and $298 for the first 3 weeks of the mont
ella [17]
385 + 326 + 298 = 1,009 / 3 = 336.33

385 + 326 + 298 + x = 350

350 x 4 = 1,400
1,400 - 1,009 = 391

385 + 326 + 298 + 391 = 1,400 / 4 = 350


The answer is $391
8 0
3 years ago
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Answer:

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Step-by-step explanation:

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2 years ago
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15x^2 + 41x + 28 <br><br>STEP BY STEP ANSWER PLSSS​
maria [59]

Answer:

(3x+4)(5x+7)

Step-by-step explanation:

15x^2 +41x+28

Factor the expression by grouping. First, the expression needs to be rewritten as 15x^2 +ax+bx+28. To find a and b, set up a system to be solved.

a+b=41

ab=15×28=420

Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 420.

1,420

2,210

3,140

4,105

5,84

6,70

7,60

10,42

12,35

14,30

15,28

20,21

Calculate the sum for each pair.

1+420=421

2+210=212

3+140=143

4+105=109

5+84=89

6+70=76

7+60=67

10+42=52

12+35=47

14+30=44

15+28=43

20+21=41

The solution is the pair that gives sum 41.

a=20

b=21

Rewrite 15x^2 +41x+28 as (15x^2 +20x)+(21x+28).

(15x^2 +20x)+(21x+28)

Factor out 5x in the first and 7 in the second group.

5x(3x+4)+7(3x+4)

Factor out common term 3x+4 by using distributive property.

(3x+4)(5x+7)

7 0
3 years ago
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Solve the equation of 4y=20 then find the value of y?
snow_tiger [21]

Answer:

y=5

Step-by-step explanation:

4 0
3 years ago
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Which of the following functions have a vertical asymptote for values of θ such that cos θ = 1? Select two answers.
valentina_108 [34]
Well costheta=1, at 0, 2pi,... 
knowing this we can exclude the first two as the are not undefined anywhere. 
tan is sin/cos, at 0 sin is also 0 so it becomes 0/1 which is 0, not undefined.
sec is1/cos, cos is 1, this is just 1
csc is 1/sin, sin is 0, 1/0 is undefined, meaning there will be an asymptote 
cot is cos/sin, this is again 1/0, so it is also an asymptote
The last two answers are the ones you want
3 0
3 years ago
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