suppose the people have weights that are normally distributed with a mean of 177 lb and a standard deviation of 26 lb.
Find the probability that if a person is randomly selected, his weight will be greater than 174 pounds?
Assume that weights of people are normally distributed with a mean of 177 lb and a standard deviation of 26 lb.
Mean = 177
standard deviation = 26
We find z-score using given mean and standard deviation
z = 
= 
=-0.11538
Probability (z>-0.11538) = 1 - 0.4562 (use normal distribution table)
= 0.5438
P(weight will be greater than 174 lb) = 0.5438
The best method for solving the system of linear equation is by the use of algebraic methods.
The system of linear equations can be solved by using the method of simultaneous equations. Here we are given two equations and two unknown variables. We can solve the same by eliminating one of the variables and then either adding or subtracting, find the value of the other variable. Once we know the value of one variable, then we can substitute its value in any one given equation and find the second variable. This method is said to be accurate and does not involve any error.
Hence answer is : USE ALGEBRAIC METHODS
Answer:
So since we have 2^-2 We can do 1/2^2 = 0.25
So if you have y^-x = 1/y^x
If you plug in the x and y of choice b you would see that it does not equal 18.
6(3) + 3(-1) = 18
18 + (-3) = 15
Answer:
The range and mean will increase - False
(because only range will increase, mean will decrease)
The mean and median will decrease - True
The mean will decrease but the median will stay the same - False
(Both of mean and median will decrease)
An outlier is more likely to change the median than the mean - False
(An outlier is more likely to change the mean than the median)
